Question

A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits the ground? (Disregard air resistance. a = −g = −9.81 m/s 2 .)

Answer 1

Initial speed of the coin (u)= 0 (As the coin is released from rest)

Acceleration due to gravity (a) = g = 9.81 m/s²

Time of fall (t) = 1.5 s

From equation of motion we have:

$\boxed{ \bf{v = u + at}}$

By substituting values in the equation, we get:

$\longrightarrow$ v = 0 + 9.81 × 1.5

$\longrightarrow$ v = 14.715 m/s

$\therefore$ Speed of the coin as it hits the ground/Final speed of the coin = 14.715 m/s