This type of listening response is called back-channel signal. This allows the speaker to know that the listener is attentive or willing to engage a conversation between them. It is shown through short utterances, facial expressions, head nods and others.
Answer:
we could use the formula, v=u+at,
65=25+a (10), a=4 , since the motion is declerating we have a=-4 m/s2
It is given that by using track and cart we can record the time and the distance travelled and also the speed of the cart can be recorded. With all this data we can solve questions on the laws of motion.
Like using the first law of motion we can determine the force of gravity acting on the cart that has moved a certain distance and the velocity or the speed of card has already been registered and since time is known putting the values in formula would help us calculate the gravitational pull acting on cart.
Answer:
The speed of ejection is 
Solution:
As per the question:
Magnetic field density, B = 0.4 T
Density of the material in the sunspot, 
Now,
To calculate the speed of ejection of the material, v:
The magnetic field energy density is given by:
This energy density equals the kinetic energy supplied by the field.
Thus
where
m = mass of the sunspot in 
= 
Answer:
θ₂ = 90° - θ₁
Explanation:
When the light falls on a mirror it bounces back. This is know as reflection. The incident angle is equal to the angle of reflection.
Here, the light strikes the mirror at an angle = θ₁
To find the angle of reflection we first need to understand angle of incidence. The angle of incidence is the angle made between the incident ray and normal. Normal is an imaginary line drawn perpendicular line on the boundary of the mirror.
Since the light strikes the mirror at angle of θ₁, which is the angle between light ray and the mirror.
Angle of incidence = 90° - θ₁.
Thus, angle of reflection, θ₂ = 90° - θ₁
