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kvasek [131]
2 years ago
14

A small car meshes with a large truck in a head-on collision. Which of the following statements concerning the magnitude of the

average collision force is correct?
A) The truck experiences the greater average force.
B) The small car and the truck experience the same average force.
C) The small car experiences the greater average force.
D) It is impossible to tell since the masses and velocities are not given.
Physics
1 answer:
RideAnS [48]2 years ago
6 0

Answer:

B

Explanation:

When ever there is a collision between two bodies , according to Newton 's third law of motion both bodies irrespective of their masses exert  force of same magnitude , in opposite direction and these forces always act in a straight line . hence B is the choice

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Cassidy Carver's family child care center has an activities table with four chairs an easel that can accommodate a child on each
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A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

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PLEEEEEAAASSSEEE HELP ME
Xelga [282]

Answer:

1) A.  0.44 m/s East + 0.33 m/s North

2) A.  0 m/s²

3) A.  a scalar calculated as distance divided by time.

4) B.  31 km per hour

Explanation:

1) Velocity is DISPLACEMENT over time.

at 1 m/s, total time of walking is 9000 seconds

displacement is 3000 m north and 5000 - 1000 = 4000 m east

4000 m/ 9000 s = 0.44 m/s E

3000 m/ 9000s = 0.33 m/s N

2) constant speed means no acceleration

3) A. a scalar calculated as distance divided by time.

4) displacement 50 km N and 80 km W

v = √(50² + 80²) / (1 + 2) = 31.446603... km/hr

3 0
1 year ago
How much does a person weigh if it takes 700 kg*m/s to move them 10 m/s<br><br> NEED ASAP
madreJ [45]

Answer:

\huge\boxed{m = 70 \ kg}

Explanation:

<u>Given Data:</u>

Momentum = P = 700 kg m/s

Velocity = v = 10 m/s

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

P = mv

<u>Solution:</u>

m = P / v

m = 700 / 10

m = 70 kg

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
5 0
1 year ago
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