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Jet001 [13]
2 years ago
13

Charina says that when waves interact with an object, they will interfere with the object, and that when waves interact with oth

er waves, they will reflect off each other. Do you agree with her? Why or why not?
Physics
2 answers:
s344n2d4d5 [400]2 years ago
7 0
No, she has it backward.  Waves interfere with each other and reflect off objects.  When two waves overlap their amplitudes add.  If they have the same sign this addition is constructive, meaning the amplitudes grow.  If they have opposite signs this constitutes subtraction and the waves can partially, or completely cancel.  This is known as interference.  Reflection occurs when waves travel from one medium to another.  If the wave impedance of the new medium is different (which it generally is) there will be a partial, or even total, reflection.  
meriva2 years ago
6 0
Sample Response:<span> I disagree with her, because interference happens when waves interact with other waves. Reflection happens when waves interact with an object and bounce off it.</span>
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A hockey puck of mass m traveling along the x axis at 4.5 m/s hits another identical hockey puck at rest. If after the collision
TEA [102]

Answer:

D) No, since kinetic energy is not conserved.

Explanation:

Since momentum is always conserved in all collision

so in Y direction we can say

0 = m(3.5 sin30) - mv_y

v_y = 1.75 m/s

Now similarly in X direction we will have

m(4.5) = m(3.5 cos30 ) + mv_x

v_x = 1.47 m/s

now final kinetic energy of both puck after collision is given as

KE_f = \frac{1}{2}m(3.5^2) + \frac{1}{2}m(1.75^2 + 1.47^2)

KE_f = 8.73 m

initial kinetic energy of both pucks is given as

KE_i = \frac{1}{2}m(4.5^2) + 0

KE_i = 10.125 m

since KE is decreased here so it must be inelastic collision

D) No, since kinetic energy is not conserved.

5 0
2 years ago
Two astronauts, A and B, both with mass of 60Kg, are moving along a straight line in the same direction in a weightless spaceshi
sveta [45]

Answer:

V=14m/s

Explanation:

From the Question we are told that

Mass of A and B is 60kg

Speed of A=2m/s

Speed of B=1m/s

Mass of bag =5kg

Generally the momentum of the astronaut  A and bag is mathematically given as

  M_A=(60+5)*2

   M_A=130kgm/s

Generally to avoid collision the speed of astronaut be should be less than or equal to that of astronaut A with the bag

Therefore for minimum requirement speed of astronaut A should be given by astronaut B's speed which is equal to 1

Therefore

  130=(60*1)=(5*v)

   V=14m/s

7 0
1 year ago
A balloon is at a height of 81m and is ascending upwards with a velocity of 12m/s. A body of 2kg weight is dropped from it. If g
kap26 [50]
I know you are Indian by your question, HC Verma class 9 or 11 !!

if you got any problem, comment !!

7 0
2 years ago
How does energy from the sun affect the motion of molecules in a gas compared to molecules in a liquid?
AnnZ [28]
Molecules in a gas move faster than in a liquid.

hope it helps.
3 0
2 years ago
Read 2 more answers
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Snezhnost [94]

Answer:

18.5 m/s

Explanation:

On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:

\mu mg = m\frac{v^2}{r}

where

\mu is the coefficient of static friction between the tires and the road

m is the mass of the car

g is the gravitational acceleration

v is the speed of the car

r is the radius of the curve

Re-arranging the equation,

v=\sqrt{\mu gr}

And by substituting the data of the problem, we find the speed at which the car begins to skid:

v=\sqrt{(0.350)(9.8 m/s^2)(100 m)}=18.5 m/s

7 0
2 years ago
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