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Amiraneli [1.4K]
2 years ago
7

A major-league pitcher throws a baseball toward home plate. The ball rotates at 1560 rpm, and it travels the 18.5 meters to the

plate at an average translational speed of 40.2 m/s. How many revolutions does the ball make during this trip?
Physics
1 answer:
DedPeter [7]2 years ago
4 0

Answer:

no of revolutions  = 56.62 rev

Explanation:

given data

rotates = 1560 rpm

travels distance = 18.5 meters

speed = 40.2 m/s

solution

first we convert here rev/min to rev/sec

rotates = 1560 rpm = 1560  × 0.0167 = 26.052 rev/sec

we get here no of revolutions that is

no of revolutions = spin rotate ÷ time    ..........1

here time = distance ÷ speed

time = 18.5 ÷  40.2  

time = 0.4601 s

put value in equation 1 we get

no of revolutions = \frac{26.052}{0.4601}  

no of revolutions  = 56.62 rev

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Tech A says that tires are marked with a date code listing the date the tires should be discarded. Tech B says that any tires wi
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Tech B is saying correct.

<u>Explanation:</u>

Yes, tires are provided with date codes but those date codes are correlated with manufacturing or production dates and not with the date of discarding. But it is difficult to understand or decode the date code. The tires with 3 digit code represent very old tires while the tires with 4 digit code are made after 1999.

In the four-digit date code, the first two digits indicate the week during which that tire was produced and the last two digits indicate the year of production. So the statement said by Tech A is wrong and the statement said by Tech B is correct.

4 0
2 years ago
The free-body diagram of a crate is shown. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N
Umnica [9.8K]

As per given conditions there are two directions along which forces are acting

1. Net force along left direction is given as

F_{left} = 352N + 176 N = 528 N

2. Net force towards right direction is given as

F_{right} = 528N + 440 N = 968 N

now since the two forces here in opposite direction so here we will have net force given as

F_{net} = F_{right} - F_{left}

F_{net} = 968 - 528

F_{net} = 440 N

so here net forces must be 440 N towards right

7 0
2 years ago
Read 2 more answers
Before leaving the house in the morning, you plop some stew in your slow cooker and turn it on Low. The slow cooker has a 160 Oh
guajiro [1.7K]

Answer:

Total charge flow through the cooker is 21600 C

Explanation:

As we know that the current flow through the cooker is given by Ohm's law

here it is given as

V = i R

i = \frac{V}{R}

i = \frac{120}{160}

i = \frac{3}{4} A

now the charge flow through it is given as

Q = i t

total time is t = 8 hours

Q = \frac{3}{4}(8 \times 60 \times 60)

Q = 21600 C

7 0
2 years ago
A uniform beam XY is 100 cm long and weighs 4.0N.The beam rests on a pivot 60 cm from end X. A load of 8.0 N hangs from the beam
Alex777 [14]

Answer:

<h2>The magnitude of force F is 18N</h2>

Explanation:

The magnitude of the force in the set up can be solved for using the principle of moment. According to the principle, the sum of clockwise moment  is equal to the sum of anticlockwise moments.

Moment = Force * perpendicular distance

Clockwise moments;

The force that acts clockwise is the unknown Force F and 4N force. If the  beam rests on a pivot 60 cm from end X and a Force F acts on the beam 80 cm from end X, the perpendicular distance of the force F from the pivot is 80-60 = 20cm and the perpendicular distance of the 4N force from the pivot is 60-50 = 10cm

Moment of force F about the pivot = F * 20

Moment of 4N force about the pivot = 4*10 = 40Nm

Sum of clockwise moment = 40+20F...(1)

Anticlockwise moment;

The  8N will act anticlockwisely about the pivot.

The distance between the 8N force and the pivot is 60-10 = 50cm

Moment of the 8N force = 8*50

=400Nm...(1)

Equating 1 and 2 we have;

40+20F = 400

20F = 400-40

20F = 360

F = 18N

The magnitude of force F is 18N

6 0
2 years ago
The average mass of an automobile in the United States is about 1.440x10^6 g express this mass in kilograms
-BARSIC- [3]
From the problem statement, this is a conversion problem. We are asked to convert from units of grams to units of kilograms. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1000 grams is equal to 1 kilogram. We use this as follows:

<span> 1.440x10^6 g ( 1 kg / 1000 g ) = 1440 kg</span><span>
</span>
8 0
2 years ago
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