Answer:
514 cal
Explanation:
In order to calculate the lost heat by the amount of water you first take into account the following formula:
(1)
Q: heat lost by the amount of water = ?
m: mass of the water
c: specific heat of water = 1cal/g°C
T2: final temperature of water = 11°C
T1: initial temperature = 12°C
The amount of water is calculated by using the information about the density of water (1g/ml):
Then, you replace the values of all parameters in the equation (1):
The amount of water losses a heat of 514 cal
Answer:
C
Explanation:
From above question we know that
A = 6.2 m
f = 1.6 rad/s
t = 3.5 s
x =?
We know that,
x = Acos(2pie ft)
Putting all values in above eq.
x = 6.2 x cos(2x3.142x1.6x3.5)
x = - 4.8
Displacement can never be negative so ignore - sign.
V = AT
v = a/2 T
d = 1/2 a T^2
d = 1/2 a/2 T^2
1/2 at^2 = 1/4 aT^2
2t^2 = T^2
T = (Sqrt2)t
Hope this helps
Answer:
B = 15μT
Explanation:
In order to calculate the magnitude of the magnetic field generated by the coaxial cable you use the Ampere's law, which is given by:
(1)
μo: magnetic permeability of vacuum = 4π*10^-7 T/A
I: current
r: distance from the wire to the point in which B is calculated
In this case you have two currents with opposite directions, which also generates magnetic opposite magnetic fields. Then, you have (but only for r > radius of the cylindrical conductor) the following equation:
(2)
I1: current of the central wire = 2.00A
I2: current of the cylindrical conductor = 3.50A
r: distance = 2.00 cm = 0.02 m
You replace the values of all parameters in the equation (2), and you use the absolute value because you need the magnitude of B, not its direction.
The agnitude of the magnetic field outside the coaxial cable, at a distance of 2.00cm to the center of the cable is 15μT
