A metal bar moves through a magnetic field. the induced charges on the bar are

If the net force acting on an object increases by 50 percent, then the acceleration of the object will

ki77a [65]

<span>If the net force acting on an object increases by 50 percent, then
the acceleration of the object will also increase by 50 percent.

This answer is not offered among the list of choices.

So the correct response is "D. none of the above"</span>

8 0

2 years ago

An electron in a vacuum chamber is fired with a speed of 9800 km/s toward a large, uniformly charged plate 75 cm away. The elect

melisa1 [442]

Answer:

The plate's surface charge density is $-8.056\times10^{-9}\ C/m^2$

Explanation:

Given that,

Speed = 9800 km/s

Distance d= 75 cm

Distance d' =15 cm

Suppose we determine the plate's surface charge density?

We need to calculate the surface charge density

Using work energy theorem

$W=\Delta K.E$

$W=\dfrac{1}{2}mv_{f}^2-\dfrac{1}{2}mv_{i}^2$

Here, final velocity is zero

$W=0-\dfrac{1}{2}mv_{i}^2$ ...(I)

We know that,

$W=-Fd$

$W=-E\times e\times d$

$W=-\dfrac{\lambda}{2\epsilon_{0}}\times e\times d$ ...(II)

From equation (I) and (II)

$-\dfrac{1}{2}mv_{i}^2=-\dfrac{\lambda}{2\epsilon_{0}}\times e\times d$

Charge is negative for electron

$\lambda=\dfrac{mv^2\epsilon_{0}}{(-e)d}$

Put the value into the formula

$\lambda=-\dfrac{9.1\times10^{-31}\times(9800\times10^{3})^2\times8.85\times10^{-12}}{1.6\times10^{-19}\times(75-15)\times10^{-2}}$

$\lambda=-8.056\times10^{-9}\ C/m^2$

Hence, The plate's surface charge density is $-8.056\times10^{-9}\ C/m^2$

3 0

2 years ago

If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

zysi [14]

Given that,

Mass of each washer = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer $m= 4.9\times10^{-3}\ Kg$

So, Mass of two washers is

$M=2\times m$

Put the value of m

$M=2\times4.9\times10^{-3}\ k$

$M=0.0098\ Kg$

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

$F=mg$

Put the value into the formula

$F=4\times4.9\times10^{-3}\times9.8$

$F=0.192\ N$

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

6 0

2 years ago

Assume that a particular person's skin is found to have a resistance of 1 x 105 Ω when dry and 1400 Ω when wet. How much current

hoa [83]

Answer:

current through dry = 1.2 mA

current through wet = 85.7 mA

Explanation:

given data

resistance dry = 1 × $10^{5}$ Ω

resistance wet = 1400 Ω

voltage applied = 120 V

to find out

current

solution

we get here current through dry skin I dry = $\frac{V}{R}$ ..................1

current = $\frac{120}{1*10^5}$ = 0.0012 A = 1.2 mA

and now we get

current through wet I wet = $\frac{V}{R}$ = $\frac{120}{1400}$ = 0.085714 A = 85.7 mA

8 0

1 year ago

A gas in a piston-cylinder device is compressed, and as a result its temperature rises. is this a heat or work interaction?

baherus [9]

The answer is both. The energy in the system is composed of heat and work. because of the temperature difference, the energy would be in the form of heat. Because of the force in executing the compression in the same direction, there is also work done.

4 0

1 year ago

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