Color <span>is a physical property of all visible light determined by the light's frequency and visible to the human eye.</span>
The static friction exerted on the block by the incline is 
.
The given parameters;
- <em>mass of the block, = M</em>
- <em>coefficient of static friction in section 1, = </em>
<em /> - <em>angle of inclination of the plane, = θ</em>
<em />
The normal force on the block is calculated as follows;
Fₙ = Mgcosθ
The static friction exerted on the block by the incline is calculated as follows;
Thus, the static friction exerted on the block by the incline is
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Answer:
294 Joules
Explanation:
From the question;
- Mass of the drum is 10 kg
- The length of inclined surface, OA is 5 m
- The final height of the drum on the plane AB is 3 m
We are required to determine the potential energy of the drum at A
We know that potential energy is given by the formula;
Potential energy = mgh
where m is the mass, g is the gravitational pull and h is the height
Taking g as 9.8 N/kg
Then;
Potential energy = 10 kg × 9.8 N/kg × 3 m
= 294 Joules
Thus, the potential energy of the drum at A is 294 Joules
Answer: B
Explanation:
Limiting the maximum current through the bulb. This will help in preserving or improving the bulb's lifetime and also this won't have an effect on the brightness of the bulb as brightness is affected by the average value. Although brightness is a factor of current, reducing the maximum current won't have any bearing on the average current the bulb is getting.
