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marta [7]
2 years ago
9

Calculate time period of a simple pendulum if it takes 72 seconds to complete 24 oscillations

Physics
1 answer:
kipiarov [429]2 years ago
8 0

72s for 24 complete oscillations.

Thus, a complete oscillation takes 72/24=3s

Answer: period T=3s

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A skydiver finds that she speeds up when she holds her arms close to her body. What does this do?
ArbitrLikvidat [17]

D. Reduces the force of air resistance

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2 years ago
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A simple pendulum 0.64m long has a period of 1.2seconds. Calculate the period of a similar pendulum 0.36m long in the same locat
weqwewe [10]

The period of the second pendulum is 0.9 s

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity at the location of the pendulum

For the first pendulum, we have

L = 0.64 m

T = 1.2 s

Therefore we can find the value of g at that location:

g=(\frac{2\pi}{T})^2 L=(\frac{2\pi}{1.2})^2 (0.64)=17.5 m/s^2

Now we can find the period of the second pendulum at the same location, which is given by

T=2\pi \sqrt{\frac{L}{g}}

where we have

L = 0.36 m (length of the  second pendulum)

g=17.5 m/s^2

Substituting,

T=2\pi \sqrt{\frac{0.36}{17.5}}=0.9 s

#LearnwithBrainly

8 0
2 years ago
Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
schepotkina [342]
If speed = distance/time , then time = speed/distance.

So...

Speed of light = 3*10^8(m/s)
Average distance from Earth to Sun = 149.6*10^9(m)

Therefore, t=(3*10^8(m/s))/(149.6*10^9(m))

I hope this was a helpful explanation, please reply if you have further questions about the problem.

Good luck!
5 0
2 years ago
It takes 300 newtons of force and a distance of 20 meters for a moving car to come to stop
Arlecino [84]
The answer is 15 I think.
6 0
2 years ago
Falling raindrops frequently develop electric charges. Does this create noticeable forces between the droplets? Suppose two 1.8
Tema [17]

Answer:

The value of developed electric force is 3.516\times 10^{- 7} N

Solution:

As per the question:

Mass of the droplet = 1.8 mg = 1.8\times 10^{- 6} kg

Charge on droplet, Q = 25 pC = 25\times 10^{- 12} C

Distance between the 2 droplets, D = 0.40 cm = 0.004 m

Now, the Electrostatic force given by Coulomb:

F_{E} = \frac{1}{4\pi epsilon_{o}}.\frac{Q^{2}}{D^{2}}

\frac{1}{4\pi epsilon_{o}} = 9\times 10^{9} m/F

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F_{E} = 3.516\times 10^{- 7} N

The magnitude of force is too low to be noticed.

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2 years ago
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