At a drag race, a jet car travels 1/4 mile in 5.2 seconds. What is the final speed of the

A man climbs a ladder. Which two quantities can be used to calculate the energy stored of the man at the top of the ladder.

Dvinal [7]

Answer:The answer must be The weight of the man and the vertical distance moved.

Explanation: you calculate it by the force you applied times the distance you moved

8 0

2 years ago

Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency ω of s

sasho [114]

Answer:

Explanation:

The general equation for the disk with moment of inertia I when given small angular displacement $\theta$ is given by

$I\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=-k\theta$

$\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}+\frac{k\theta }{I}=0$

Replacing

$\frac{k\theta }{I}=\omega ^2$

where $\omega$ is the angular frequency of oscillation

General solution for this Equation is given by

$\theta =\theta _{max}\sin \left ( \omega t+\phi \right )$

where $\theta _{max}=maximum\ angular\ displacement$

$\phi =Phase\ difference$

Thus K can be written as

$k=I\omega ^2$

5 0

2 years ago

Which of the following is the BEST example of increasing the intensity of a workout? A. running one mile further than normal B.

stepladder [879]

Answer:

B. running one mile faster than normal

Explanation:

4 0

2 years ago

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A pump lifts water from a lake to a large tank 20 m above the lake. How much work against gravity does the pump do as it transfe

Aleonysh [2.5K]

Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

3 0

2 years ago

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Jade and her roommate Jari commute to work each morning, traveling west on I-10. One morning Jade left for work at 6:45 A.M., bu

Veronika [31]

Answer:

Jari

Explanation:

The question requires to know who is traveling faster. This is done by comparing the gradients. The steeper the slope (high gradient), the faster the speed and vice versa.

From Jari's line, the starting point is (0, 0) and another point is (6, 7)

The gradient being change in y to change in x

Change in y=7-0=7

Change in x=6-0=6

Slope is 7/6

For Jade, first point is (0, 10) then another point is (6, 16)

Change in y=16-10=6

Change in x=6-0=6

Slope is 6/6=1

Clearly, 7/6 is greater than 6/6 or 1 hence Jari is faster than Jade

3 0

2 years ago