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Ann [662]
2 years ago
14

Which was the first object made by humans to orbit earth?

Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
6 0

The first human made object made to orbit earth was the Soviet Union's Sputnik 1, it launched the 4th of October 1957.

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Janelle wants to buy some strings of decorative lights for her home. She is trying to decide between two strings of lights that
inysia [295]
If she has a choice and the wiring details are stated on the packaging,
then Janelle should look for lights that are wired in parallel within the
string, and she should avoid lights that are wired in series within the string. 

If a single light in a parallel string fails, then only that one goes out. 
The rest of the lights in the string continue to shimmer and glimmer.

If a single light in a series string fails, then ALL of the lights in that string
go out, and it's a substantial engineering challenge to determine which light
actually failed.
6 0
2 years ago
Read 2 more answers
An object weighs 980N on the earth’s surface (i) What is its mass? (ii) If the same object weighs 360N on another planet, find t
AnnZ [28]
Weight = mass*gravity. Hence mass = 980/9.8 = 100kg. Gravity of planet 2 = weight/mass = 3.6 m/s^2
4 0
2 years ago
Two friends of different masses are on the playground. They are playing on the seesaw and are able to balance it even though the
Westkost [7]

Answer:

They are able to balance torques due to gravity.

F_1 L_1 = F_2L_2

Explanation:

When two friends of different masses will balance themselves on see saw then at equilibrium position the see saw will remain horizontal

This condition will be torque equilibrium position where the see saw will not rotate

Here we can say

F_1 L_1 = F_2L_2

here we know that force is due to weight of two friends

and their positions are different with respect to the lever about which see saw is rotating

since both friends are of different weight so they will balance themselves are different positions as per above equation

5 0
2 years ago
What resistance must be connected in parallel with a 633-Ω resistor to produce an equivalent resistance of 205 Ω?
alukav5142 [94]

Answer:

303 Ω

Explanation:

Given

Represent the resistors with R1, R2 and RT

R1 = 633

RT = 205

Required

Determine R2

Since it's a parallel connection, it can be solved using.

1/Rt = 1/R1 + 1/R2

Substitute values for R1 and RT

1/205 = 1/633 + 1/R2

Collect Like Terms

1/R2 = 1/205 - 1/633

Take LCM

1/R2 = (633 - 205)/(205 * 633)

1/R2 = 428/129765

Take reciprocal of both sides

R2 = 129765/428

R2 = 303 --- approximated

5 0
2 years ago
Find an expression for the torsional constant k in terms of the moment of inertia I of the disk and the angular frequency ω of s
sasho [114]

Answer:

Explanation:

The general equation for the disk with moment of inertia I when given small angular displacement  \theta is given by

I\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=-k\theta

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}+\frac{k\theta }{I}=0

Replacing

\frac{k\theta }{I}=\omega ^2

where \omega is the angular frequency of oscillation

General solution for this Equation is given by

\theta =\theta _{max}\sin \left ( \omega t+\phi \right )

where \theta _{max}=maximum\ angular\ displacement

\phi =Phase\ difference

Thus K can be written as

k=I\omega ^2

5 0
2 years ago
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