Answer:3.87*10^-4
Explanation:
What is the decrease in mass, delta mass Xe , of the xenon nucleus as a result of this deca
We have been given the wavelength of the gamma ray, find the frequency using c = freq*wavelength.
C=f*lambda
3*10^8=f*3.44*10^-12
F=0.87*10^20 hz
Then with the frequency, find the energy emitted using equation
E=hf E = freq*Plank's constant
E=.87*10^20*6.62*10^-34
E=575.94*10^(-16)
With this energy, convert into MeV from joules.
With the energy in MeV, use E=mc^2 using c^2 = 931.5 MeV/u.
Plugging and computing all necessary numbers gives you
3.87*10^-4 u.
Answer:
A) The new amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please find the attached files for the solution
Answer:
Electric field, 
Explanation:
It is given that,
Magnitude of charge, 
Force experienced, 
We need to find the electric field at the origin. It is given by :
So, the electric field at the origin is 
. Hence, this is the required solution.
Answer:
They are rechargeable
They have a longer life span
They are reusable
Explanation:
Lead acid accumulators and leclanche cells are types of electrochemical cells.
Leclanche cells are primary cells. Primary cells produce chemical reactions through which the electric current generated is irreversible.
Lead Acid Accumulators are secondary cells in which electric current generated is reversible.
This makes lead acid accumulators reusable, more durable and they have a longer life span.
