Question

) What is the electric potential due to the nucleus of hydrogen at a distance of 7.50× 10-11 m? Assume the potential is equal to zero as r→∞. (Express your answer to three significant figures.)

Answer 1

For this, we need the formula:
V = k q / r
where k is the Coulombs law constant = 9 x 10^9 N
q is the charge of the hydrogen nucleus (proton) = 1.6 x 10^-19 C 
r is the distance
Simply plug in the values and solve for V

Answer 2

Answer:

Electric potential, V = 19.2 volts

Explanation:

In this case we need to find the electric potential due to the nucleus of hydrogen at a distance of $7.5\times 10^{-11}\ m$. For this we must know the concept of electric potential. It is the work done in moving a charged particle in electric field from zero to a particular point. Its formula is given by :

$V=\dfrac{kq}{r}$

q is the charge of nucleus of hydrogen i.e. proton

$V=\dfrac{9\times 10^9\times 1.6\times 10^{-19}}{7.5\times 10^{-11}}$

$V=19.2\ \text{volt}$

So, the electric potential due to the nucleus of hydrogen at a given distance is 19.2 volts. Hence, this is the required solution.