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Vinil7 [7]
2 years ago
14

A wave travels through a medium at 251 m/s and has a wavelength of 5.10 cm. What is its frequency? What is its angular frequency

? What is its period of oscillation?
Physics
1 answer:
allochka39001 [22]2 years ago
5 0

Explanation:

It is given that,

Speed of a wave, v = 251 m/s

Wavelength of the wave, λ = 5.1 cm = 0.051 m

(1) The frequency of the wave is given by :

\nu=\dfrac{v}{\lambda}

\nu=\dfrac{251\ m/s}{0.051\ m}

\nu=4921.56\ Hz

(2) Angular frequency of the wave is given by :

\omega=2\pi\nu

\omega=2\pi\times 4921.56\ Hz

\omega=30923.07\ rad/s

(3) The period of oscillation is given by T as :

T=\dfrac{1}{\nu}

T=\dfrac{1}{4921.56}

T = 0.000203 seconds

or

T = 0.203 milliseconds

Hence, this is the required solution.

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A.Whale communication. Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard n
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\lambda=\frac{v}{f}

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B. 102 kHz

We can re-arrange the same equation used previously to solve for the frequency, f:

f=\frac{v}{\lambda}

where for the dolphin:

v = 1531 m/s is the wave speed

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f=\frac{1531 m/s}{0.015 m}=1.02 \cdot 10^5 Hz=102 kHz

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\lambda=\frac{v}{f}

where

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The frequency will be

f=\frac{v}{\lambda}=\frac{1550 m/s}{2.5\cdot 10^{-4} m}=6.2\cdot 10^6 Hz=6.2 MHz

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