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tekilochka [14]
2 years ago
7

Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.9 m tall window in 0.134 sec. From how high above th

e top of the window was the rock dropped? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.
Physics
1 answer:
timama [110]2 years ago
8 0

Answer:

Explanation:

Given

length of window h=2.9\ m

time Frame for which rock can be seen is \Delta t=0.134\ s

Suppose h is height above which rock is dropped

Time taken to cover h+2.9 is t_1

so using equation of motion

y=ut+\frac{1}{2}at^2

where  y=displacement

u=initial velocity

a=acceleration

t=time

time taken to travel h  is

h=0+0.5\times g\times (t_2)^2---2

Subtract 1 and 2 we get

2.9=0.5g(t_1^2-t_2^2)

5.8=g(t_1+t_2)(t_1-t_2))

and from equation t_1-t_2=0.134\ s

so t_1+t_2=\frac{5.8}{9.8\times 0.134}

t_1+t_2=4.416\ s

and t_1=t_2+\Delta t

so t_2+\Delta t+t_2=4.416

2t_2+0.134=4.416

t_2=0.5\times 4.282

t_2=2.141\ s

substitute the value of t_2 in equation 2

h=0.5\times 9.8\times (2.141)^2

h=22.46\ m

                                                     

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Ostrovityanka [42]

Answer:

a)  N = 9 Mg

, b)N_w =  μ 9M

, c)  

Explanation:

a) For this part we write the equations of trslacinal equilibrium

Axis y

       N - Mg - 8M g = 0

       N = 9 Mg

        N = 9 11 9.8

        N = 970.2 N

b) the force on the horizontal axis (x) som

        fr -N_w = 0

        fr = N_w

friction force is

       fr = μ N

      N_w =  μ 9M

g

      fr = 0.59 970.2

      fr = N_w = 572,418 N

c) For this part we must use rotational equilibrium.

         Στ = 0

We set a frame of reference at the bottom of the ladder and assume that the counterclockwise acceleration is positive

the weight of it is at its midpoint (L / 2)

      - W L /2 cos 54 - 8M d_max cos 54+ NW L sin 54 = 0

        8M d_max cos 54 = - W L / 2 cos 54 + NW L sin 54

       d_max = L (-Mg 1/2 cos 54 + NW sin 54) / (8M cos 54)

       d_max = L (-g / 16 + μ 9Mg / 8M tan 54)

       d_max = L ( 9/8 μ g tan 54- g/16)

   

3 0
2 years ago
Two vectors, r and c, are equal: r = c. Which of the following statements are true? (Select all that apply.)
s344n2d4d5 [400]

Answer:

(A) The y-component of r must be equal to the y-component of c

(B) The x-component of r must be equal to the x-component of c

(C) The z-component of r must be equal to the z-component of c

(F) The unit vector r must be equal to the unit vector c.

Explanation:

If two vectors are equal there are some conditions must be satisfy for the two vectors to be equal.

Let us suppose 2 vectors as,

A=a_{1}i+ a_{2}j+a_{3}k and

B=b_{1}i+ b_{2}j+b_{3}k

The conditions for the above two vectors should be equal are:

(1) a_{1}=b_{1}, a_{2}=b_{2}, and a_{3}=b_{3}.

(2) Unit vector of A must be equal to unit vector of B.

(3) Magnitude of both the vectors should be equal.

Now, according to question and observing above conditions of equality for r and c to be equal, the statements should be true are:

(A) The y-component of r should be equal to the y-component of c

(B) The x-component of r should be equal to the x-component of c

(C) The z-component of r should be equal to the z-component of c

(F) The unit vector r should be equal to the unit vector c.

6 0
2 years ago
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to thenext handhold. A 9.3kggibbon has
Mumz [18]

Upward force provided by the branch is 260 N

<u>Explanation:</u>

Given -

Mass of Gibbon, m = 9.3 kg

Length of the branch, r = 0.6 m

Speed of the movement, v = 3.3 m/s

Upward force, T = ?

The tension force in the rod must be greater than the weight at the bottom of the swing in order to provide an upward centripetal acceleration.

Therefore,

F net = T - mg

F net = ma = mv²/r

Thus,

T = mv²/r + mg

T = m ( v²/r + g)

T = 9.3 [ ( 3.3)² / 0.6 + 9.8]

T = 259.9 N ≈ 260 N

Therefore, upward force provided by the branch is 260 N

5 0
1 year ago
A ball is thrown into the air and follows the parabolic path indicated by the dashed line. Use the arrows provided to indicate t
avanturin [10]

Answer:

Trajectory is the path of a projectile in air. Any tangential to the curve shows it velocity and the slope of the tangential line will be it acceleration.

Explanation:

5 0
1 year ago
Write a conclusion to this lab in which you discuss when a person on a roller coaster ride would have sensations of weightlessne
masya89 [10]

Answer:

he lower part of the curve     N = M (g + v² / r)

upper part of the curve          N = m (v² /r -g)

Explanation:

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These sensations can be explained using Newton's second law, let's apply it to the lower part of the curve

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acceleration is centripetal

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we substitute

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        N = M (g + v² / r)

In this part the apparent weight is increased by the speed of the body squared, it feels like a lot of fart.

In the upper part of the curve the force of gravity continues to act downwards, the normal that is the reaction of the surface also goes downwards, the centripetal acceleration pointing towards the center of the curve has a vertical downward direction

        -N -W = -m a

         N = ma -W

         N = m (v² / r -g)

In this case we see that the normal that gives the sensation decreases, which is why we feel a loss of weight, in the case of v2 / r = g, the request is total and the sensation of weightlessness.

3 0
1 year ago
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