answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ilya [14]
2 years ago
6

A boat is headed with a velocity of 18 meters/second toward the west with respect to the water in a river. If the river is flowi

ng with a velocity of 2.5 meters/second in the same direction as the boat. What would be the magnitude of the boat’s velocity?
Physics
1 answer:
IrinaK [193]2 years ago
7 0
If the boat's velocity is 18m/sec relative to the water in the river and not the shore, it would need to be added the river speed of 2.5m/sec to get a total of 20.5m/sec. The 20.5m/sec would then be the total velocity of the boat relative to the shore. From personal experience, I know that when one runs with the tide, one is adding the tide flow speed to one's boat speed (what it would be in neutral waters) to get a sometimes much faster speed.
You might be interested in
A simple pendulum of length 2.5 m makes 5.0 complete swings in 16 s. What is the acceleration of gravity at the location?
Norma-Jean [14]
<h2>The acceleration of gravity at the location is 9.64 m/s²</h2>

Explanation:

Length of pendulum = 2.5 m

Time taken for 5 swings = 16 seconds

Time taken for 1 swing = 3.2 seconds

Period of pendulum = 3.2 seconds.

We have equation for period of simple pendulum as

             T=2\pi \sqrt{\frac{l}{g}}

Where l is the length of pendulum and g is acceleration due to gravity.

Substituting

                 T=2\pi \sqrt{\frac{l}{g}}\\\\3.2=2\pi \sqrt{\frac{2.5}{g}}\\\\g=\frac{4\pi^2 \times 2.5}{3.2^2}\\\\g=9.64m/s^2

The acceleration of gravity at the location is 9.64 m/s²

8 0
1 year ago
A 18.0−μF capacitor is placed across a 22.5−V battery for a few seconds and is then connected across a 12.0−mH inductor that has
Gelneren [198K]

Answer:

Part a)

i = 10.4 mA

Part b)

in this case the charge on the capacitor will become zero

Part c)

t_1 = 0.73 ms

Part d)

t = 2.2 ms

Explanation:

As we know that first capacitor is charged with the battery and then it is connected to the inductor

So here we will have

Q = CV

Q = (18\mu F)(22.5 V)

Q = 405 \mu C

Part a)

now since the total energy of capacitor is converted into the energy of inductor

so by energy conservation we can say

\frac{Q^2}{2C} = \frac{1}{2}Li^2

so maximum current is given as

i = \sqrt{\frac{L}{C}}Q

i = \sqrt{\frac{12\times 10^{-3}}{18\times 10^{-6}}}(405\times 10^{-6})

i = 10.4 mA

Part b)

When current is maximum then whole energy of capacitor is converted into magnetic energy of inductor

So in this case the charge on the capacitor will become zero

Part c)

Time period of oscillation of charge between the plates and inductor is given as

T = 2\pi\sqrt{LC}

T = 2\pi\sqrt{(18\mu F)(12 mH)}

T = 2.92 ms

now capacitor gets discharged first time after 1/4 of total time period

t_1 = 0.73 ms

Part d)

Since time period is T and capacitor gets discharged two times in one complete time period of the motion

so first it will discharges in T/4 time

then next T/4 it will get charged again

then next T/4 time it will again discharged

so total time taken

t = 3T/4

t = 2.2 ms

4 0
1 year ago
The velocity of a an object in linear motion changes from +25 meters per second to +15 meters per second in 2.0 seconds.
kodGreya [7K]

Answer:

-5.0 m/s^2

Explanation:

Missing question:

What is the object's acceleration?

Solution:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time taken for the change in velocity

For the object in this problem,

u = +25 m/s

v = +15 m/s

t = 2.0 s

Substituting,

a=\frac{15-25}{2}=-5.0 m/s^2

And the acceleration is negative because its direction is opposite to that of the velocity.

5 0
2 years ago
A section of highway has the following flowdensity relationship q = 50k − 0.156k2 [with q in veh/h and k in veh/mi]. What is the
lions [1.4K]

Answer:

a) capacity of the highway section = 4006.4 veh/h

b) The speed at capacity = 25 mph

c) The density when the highway is at one-quarter of its capacity = k = 21.5 veh/mi or 299 veh/mi

Explanation:

q = 50k - 0.156k²

with q in veh/h and k in veh/mi

a) capacity of the highway section

To obtain the capacity of the highway section, we first find the k thay corresponds to the maximum q.

q = 50k - 0.156k²

At maximum flow density, (dq/dk) = 0

(dq/dt) = 50 - 0.312k = 0

k = (50/0.312) = 160.3 ≈ 160 veh/mi

q = 50k - 0.156k²

q = 50(160.3) - 0.156(160.3)²

q = 4006.4 veh/h

b) The speed at the capacity

U = (q/k) = (4006.4/160.3) = 25 mph

c) the density when the highway is at one-quarter of its capacity?

Capacity = 4006.4

One-quarter of the capacity = 1001.6 veh/h

1001.6 = 50k - 0.156k²

0.156k² - 50k + 1001.6 = 0

Solving the quadratic equation

k = 21.5 veh/mi or 299 veh/mi

Hope this Helps!!!

3 0
2 years ago
A spaceship which is 50,000 kilometers from the center of Earth has a mass of 3,000 kilograms. What is the magnitude of the forc
Anna11 [10]
Fg=Gx(M1M2/r^2)
Fg=478N
6 0
2 years ago
Read 2 more answers
Other questions:
  • Two negative charges that are both -0.3C push each other apart with a force of 19.2 N. How far apart are the two charges?
    15·1 answer
  • Consider two objects whose masses are 100 g and 200 g. The smaller object strikes the larger object with a force of 500 N. Accor
    11·2 answers
  • A tennis player who is recovering from an ankle injury and is not allowed to change directions can maintain her cardio fitness l
    12·2 answers
  • 0 the period of a pendulum is the time it takes the pendulum to swing back and forth once. if the only dimensional quantities th
    6·1 answer
  • A rare and valuable antique chest is being moved into a truck using a 4.00 m long ramp. the kj weight of the chest plus packing
    9·1 answer
  • A plane traveled west for 4.0 hours and covered a distance of 4,400 kilometers. What was its velocity? 18,000 km/hr 1,800 km/hr,
    12·2 answers
  • Consider a finite square-well potential well of width 3.1 ✕ 10-15 m that contains a particle of mass 1.8 GeV/c2. How deep does t
    9·1 answer
  • In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg,
    11·2 answers
  • A person ate 0.50 pound of cheese (an energy intake of 4000 kJ). Suppose that none of the energy was stored in his body. What ma
    14·1 answer
  • What speed would a fly with a mass of 0.55g need in order to have a kinetic energy of 7.6 •10^4 j?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!