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1 year ago

7

A cyclist moving towards right with an acceleration of 4m/s² at t = 0 he has travelled 5 m moving towards the right at 15 m/s wh

at will be his final position

1 answer:

ira [324]1 year ago

4 0

Answer:

$x=2t^2+15t+5$

Explanation:

$x=\frac{1}{2}at^2+v_0t+x_0$

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A 2.00-kg box is suspended from the end of a light vertical rope. A time-dependent force is applied to the upper end of the rope

Alex

Answer:

T = 27.92 N

Explanation:

For this exercise let's use Newton's second law

T - W = m a

The weight

W = mg

The acceleration can be found by derivatives

a = dv / dt

v = 2 t + 0.6 t²

a = 2 + 0.6 t

We replace

T - mg = m (2 + 0.6t)

T = m (g + 2 + 0.6 t) (1)

Let's look for the time for the speed of 15 m / s

15 = 2 t + 0.6 t²

0.6 t² + 2 t - 15 = 0

We solve the second degree equation

t = [-2 ±√(4 - 4 0.6 (-15))] / 2 0.6

t = [-2 ±√40] / 1.3 = [-2 ± 6.325] / 1.2

We take the positive time

t = 3.6 s

Let's calculate from equation 1

T = 2.00 (9.8 + 2 + 0. 6 3.6)

T = 27.92 N

4 0

2 years ago

A wire loop is suspended from a string that is attached to point P in the drawing. When released, the loop swings downward, from

Naddik [55]

Complete Question

The complete question iws shown on the first uploaded image

Answer:

a

$y \to z \to x$

b

$x \to z \to y$

Explanation:

Now looking at the diagram let take that the magnetic field is moving in the x-axis

Now the magnetic force is mathematically represented as

$F = I L$ x B

Note (The x is showing cross product )

Note the force(y-axis) is perpendicular to the field direction (x-axis)

Now when the loop is swinging forward

The motion of the loop is from y to z to to x to y

Now since the force is perpendicular to the motion(velocity) of the loop

Hence the force would be from z to y and back to z

and from lenze law the induce current opposes the force so the direction will be from y to z to x

Now when the loop is swinging backward

The motion of the induced current will now be x to z to y

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2 years ago

Sara and Saba are identical twins who are the same in every way, including their weights. One day, Sara and Saba decided to go f

Sphinxa [80]

As Saba was wearing high heels they are long from the bottom so they sank however Sana was wearing snow boots which means they were flat and so she didn’t sink.

3 0

2 years ago

3. A 64 lb weight stretches a spring 4 ft in equilibrium. The weight is initially displaced 6 inches above equilibrium and given

Damm [24]

Answer:

Explanation:

the solution is given in the attached pictures

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2 years ago

You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t

kati45 [8]

Answer:

The coefficient of kinetic friction $\mu_k = 0.724$

Explanation:

From the question we are told that

The length of the lane is $l = 36.0 \ m$

The speed of the truck is $v = 22.6\ m/s$

Generally from the work-energy theorem we have that

$\Delta KE = N * \mu_k * l$

Here N is the normal force acting on the truck which is mathematically represented as

$\Delta KE$ is the change in kinetic energy which is mathematically represented as

$\Delta KE = \frac{1}{2} * m * v^2$

=> $\Delta KE = 0.5 * m * 22.6^2$

=> $\Delta KE = 255.38m$

$255.38m = m * 9.8 * \mu_k * 36.0$

=> $255.38 = 352.8 * \mu_k$

=> $\mu_k = 0.724$

6 0

2 years ago