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goldfiish [28.3K]
2 years ago
15

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

questions. "Ethics in Research" What ethical issues have been raised by the scientific community's commitment to ensuring that experimental treatments are not used on patients?
Physics
1 answer:
nataly862011 [7]2 years ago
6 0

Answer:

The major ethical issues in leading examination are: an) Informed assent, b) Beneficence-Do not hurt c) Respect for obscurity and secrecy d) Respect for security.

Explanation:

The major ethical issues in leading examination are: an) Informed assent, b) Beneficence-Do not hurt c) Respect for obscurity and secrecy d) Respect for security.

There are a few reasons why it is essential to stick to ethical norms in research. To start with, standards advance the points of exploration, for example, information, truth, and shirking of blunder. For instance, preclusions against creating, adulterating, or distorting research information advance reality and limit mistake.

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Calculate the volume of a liquid with a density of 5.45 g/ml and a mass of 65g
katrin [286]
Density=mass/volume
5.45g/ml=65g/V
V=65g/5.42g/ml
V=11.92ml
5 0
2 years ago
Consider a sign suspended on a boom that is supported by a cable, as shown. What is the proper equation to use for finding the n
oksian1 [2.3K]
Fnety = (FT)(sin 32°) – Fg Or the answer B, I checked it.
3 0
2 years ago
Read 2 more answers
A gas laser has a cavity length of 1/3 m and a single oscillation frequency of 9.0 x 1014 Hz. What is the cavity mode number?
Eddi Din [679]

Answer:

2 × 10⁶

Explanation:

Data provided in the question:

Cavity length, L = \frac{1}{3}m

Oscillation frequency, f_m = 9.0 × 10¹⁴ Hz

Now,

we know,

f_m=\frac{c}{\lambda_m}

here,

c is the speed of light = 3 × 10⁸ m/s

\lambda_m = Wavelength of mode m inside the laser cavity

m is the cavity mode number

Thus,

9.0\times10^{14}=\frac{3\times10^8}{\lambda_m}

or

\lambda_m = \frac{1}{3} × 10⁻⁶

Also,

m\lambda_m = 2L

Therefore,

m × \frac{1}{3} × 10⁻⁶ = 2 × \frac{1}{3}

or

m = 2 × 10⁶

5 0
2 years ago
Determine the length of a copper wire that has a resistance of 0.172 ? and cross-sectional area of 7.85 × 10-5 m2. The resistivi
KonstantinChe [14]

Answer:

Length of copper wire, l = 785 meters

Explanation:

Given that,

Resistance of the copper wire, R = 0.172 ohms

Area of cross section, A=7.85\times 10^{-5}\ m^2

Resistivity of copper, \rho=1.72\times 10^{-8}\ \Omega-m

The resistance of a wire is given by :

R=\rho\dfrac{l}{A}

l=\dfrac{RA}{\rho}

l=\dfrac{0.172\ \Omega\times 7.85\times 10^{-5}\ m^2}{1.72\times 10^{-8}\ \Omega-m}

l = 785 meters

So, the length of the copper wire is 785 meters. Hence, this is the required solution.

8 0
2 years ago
If Emily throws the ball at an angle of 30∘ below the horizontal with a speed of 12m/s, how far from the base of the dorm should
Hitman42 [59]

Answer:

3.6 m

Explanation:

let x = horizontal distance between emily and allison should be for allison to catch the ball

Find horizontal speed of the ball

vx = 12 sin 30 = 12 x 0.5 = 6 m/s

To find time taken, we will use vertical values of the ball motion

Initial velocity in vertical direction

u = 12 cos 30 = 10.392 m/s

let a = g = 9.8m/s2

Use equation of motion

s = ut +1/2at^2

s = vertical distance = 8

8 = (10.392)t + (1/2)(9.8)t^2

8 = (10.392)t + (4.9)t^2

4.9t^2 + 10.392t - 8 = 0

Using formula of quadratic or calculator, we'll find

t = 0.6 and t = -2.72

We pick t=0.6s since it's not logical time in negative

Assuming no air resistance or external forces, the ball will move 6m/s horizontally. Hence using the formula of speed

speed vx = distance x / time

x = (vx)(t)

  = 6 x 0.6

  = 3.6 m

6 0
2 years ago
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