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rjkz [21]
1 year ago
6

Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 8.6 kg gibbon

has an arm length (hand to shoulder) of 0.60 mm. We can model its motion as that of a point mass swinging at the end of a 0.60-mm-long, massless rod. At the lowest point of its swing, the gibbon is moving at 3.5 m/s.
Required:
What upward force must a branch provide to support the swinging gibbon?
Physics
1 answer:
fiasKO [112]1 year ago
5 0

Answer:

Explanation:

i dont knoe sorry

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A boy does 465 J of work pulling an empty wagon along level ground with a force of 111 N [31o below the horizontal]. A frictiona
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A monoatomic ideal gas undergoes an isothermal expansion at 300 K, as the volume increased from 0.010 m^3 to 0.040 m^3. The fina
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Answer:

A) 0.0 kJ

Explanation:

Change in the internal energy of the gas is a state function

which means it will not depends on the process but it will depends on the initial and final state

Also we know that internal energy is a function of temperature only

so here the process is given as isothermal process in which temperature will remain constant always

here we know that

\Delta U = \frac{3}{2}nR\Delta T

now for isothermal process since temperature change is zero

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Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
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Please see attachment

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Please see attachment

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Pistons are fitted to two cylindrical chambers connected through a horizontal tube to form a hydraulic system. The piston chambe
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Answer:

order   d> a = e> c> b = f

Explanation:

Pascal's law states that a change in pressure is transmitted by a liquid, all points are transmitted regardless of the form

      P₁ = P₂

Using the definition of pressure

      F₁ / A₁ = F₂ / A₂

      F₂ = A₂ /A₁   F₁

Now we can examine the results

a) F1 = 4.0 N A1 = 0.9 m2 A2 = 1.8 m2

     F₂ = 1.8 / 0.9 4

     F₂a = 8 N

b) F1 = 2.0 N A1 = 0.9 m2 A2 = 0.45 m2

    F₂b = 0.45 / 0.9 2

    F₂b = 1 N

c) F1 2.0 N A1 = 1.8 m2 A2 = 3.6 m2

    F₂c = 3.6 / 1.8 2

    F₂c = 4 N

d) F1 = 4.0N A1 = 0.45 m2 A2 = 1.8 m2

    F₂d = 1.8 / 0.45 4.0

    F₂d = 16 m2

e) F1 = 4.0 N A1 = 0.45 m2 A2 = 0.9 m2

   F₂e = 0.9 / 0.45 4

   F₂e = 8 N

f) F1 = 2.0N A1 = 1.8 m2 A2 = 0.9 m2

   F₂f = 0.9 / 1.8 2.0

   F₂f = 1 N

Let's classify the structure from highest to lowest

F₂d> F₂a = F₂e> F₂c> F₂b = F₂f

I mean the combinations are

 d> a = e> c> b = f

6 0
2 years ago
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