b) Equal to 243 N.
Explanation:
The total force acting on the car in the opposite direction including the road friction and air resistance is equal to 243 N.
This is in conformity with newton's third law of motion.
Newton's third law of motion states that "action and reaction are equal and opposite in direction. "
- The action force is that of the pull by Harry acting on the car.
- The reaction force is in the opposite direction.
- Both action and reaction force equal and opposite and magnitude and direction
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Answer:
Rod 1 has greater initial angular acceleration; The initial angular acceleration for rod 1 is greater than for rod 2.
Explanation:
For the rod 1 the angular acceleration is
Similarly, for rod 2

Now, the moment of inertia for rod 1 is
,
and the torque acting on it is (about the center of mass)

therefore, the angular acceleration of rod 1 is


Now, for rod 2 the moment of inertia is


and the torque acting is (about the center of mass)


therefore, the angular acceleration
is


We see here that

therefore

In other words , the initial angular acceleration for rod 1 is greater than for rod 2.
Answer:
pu = 1260.9kg/m^3
the density of the unknown liquid is 1260.9kg/m^3
Explanation:
The density of a liquid is inversely proportional to the volume (height) of object submerged in it.
High density liquid possess higher buoyant force preventing objects from submerging.
p ∝ 1/V ∝ 1/h
since V = Ah
pu/pw = hw/hu
pu = pwhw/hu
Where;
p = density
h = height submerged
pu and pw is the density of unknown liquid and water respectively
hu and hw is the height of object submerged in unknown liquid and water respectively
pw = 1000kg/m^3
hu = 4.6cm = 0.046m
hw = 5.8cm = 0.058m
Substituting the given values;
pu = 1000×0.058/0.046
pu = 1260.9kg/m^3
the density of the unknown liquid is 1260.9kg/m^3
Answer:
a) Fₓ = 23.5 N
b) Net force = Fₓ
Explanation:
An image of the question as described is attached to this solution.
From the image attached, the forces acting on the box include the weight of the box, the normal reaction of the surface on the box, the applied force on the box and the Frictional force opposing the motion of the box (which is negligible and equal to 0)
a) From the diagram, the horizontal component of the force is
Fₓ = 25 cos 20° = 23.49 N = 25 N
b) Again, from the diagram attached, doing a force balance on the box, in the horizontal direction, we obtain
Net force = Fₓ - Frictional force
But frictional force is 0 N
Net force = Fₓ
Hope this Helps!!!