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1 year ago

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A rock is thrown down from the top of a cliff with a velocity of 3.61 m/s (down). The cliff is 28.4 m above the ground. Determin

e the velocity of the rock just before it hits the ground.

1 answer:

Katarina [22]1 year ago

4 0

I’m not sure look it up in the internet!

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A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe

Nonamiya [84]

Answer:

6.78 X 10³ N/C

Explanation:

Electric field near a charged infinite plate

= surface charge density / 2ε₀

Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.

Field due to charge density of +95.0 nC/m2

E₁ = 95 x 10⁻⁹ / 2 ε₀

Field due to charge density of -25.0 nC/m2

E₂ = 25 x 10⁻⁹ / 2ε₀

Total field

E = E₁ + E₂

= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ / 2ε₀

= 6.78 X 10³ N/C

4 0

2 years ago

A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the m

Marrrta [24]

Answer:

$-1.47 m/s^2$

Explanation:

We can use the following SUVAT equation to solve the problem:

$v^2 - u^2 = 2ad$

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d = 196 m is the displacement of the car before coming to a stop

Solving the equation for a, we find the acceleration:

$a=\frac{v^2-u^2}{2d}=\frac{0-(24)^2}{2(196)}=-1.47 m/s^2$

4 0

2 years ago

Four different observers are standing in a straight line on a street and hear a siren from a police car. Each person recorded th

Amanda [17]

Answer:

Wycleff is on block 1, Lilly is on block 4, Emilia is on block 12, and Quincy is on block 17.

Explanation:

Wycleff was at block 1 and heard a low pitch sound the whole time, so the police car must have been moving away from him.

Lilly observed was in block 4 change in pitch first. So the car must have passed her first.

Emilia was at block 12 observed a Doppler effect after Lilly. So the car passed her after passing Lilly

Quincy was at block 17 so she heard a high pitch sound the whole time, so the police car must have been moving toward him.

7 0

2 years ago

An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s,

timama [110]

Answer:

The length of open-open pipe needed is 6.23 m

The length of open-close pipe needed is 3.11 m

Explanation:

Fundamental frequency for standing wave mode of an open- open pipe is given by

$f=\frac{v}{2L}$

where v is the velocity and L is the length

The length of open-open pipe needed is

$L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m$

Fundamental frequency for standing wave mode of an open- close pipe is given by

$f=\frac{v}{2L}$

The length of open-close pipe needed is

$L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m$

7 0

2 years ago

Okno okrętu podwodnego ma powierzchnię 0,3 m2 i znajduje się na głębokości, na której ciśnienie wywierane przez słup wody wynosi

muminat

Answer:

Wartość siły nacisku wody na okno wynosi 150000 N.

The value of the water pressure force on the window is 150,000 N.

Explanation:

Kompletne pytanie

Okno okrętu podwodnego ma powierzchnię 0,3 m2 i znajduje się na głębokości, na której ciśnienie wywierane przez słup wody wynosi 500 kPa. Dokończ zdanie. Wartość siły parcia wody na okno wynosi.

Rozwiązanie

Ciśnienie wywierane przez siłę na pole powierzchni prostopadłe do linii działania tej siły jest określone wzorem

P = (F / A)

gdzie F = przyłożona siła, w tym przypadku siła nacisku wody na okno =?

A = Obszar, na który działa siła = Powierzchnia okna = 0,3 m²

P = 500 kPa = 500000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

Mam nadzieję że to pomoże!!!

Complete Question In English

The submarine window has an area of 0.3 m2 and is located at a depth at which the pressure exerted by the water column is 500 kPa. Finish the sentence. The value of the water pressure force on the window is.

Solution

Pressure exerted by a force on a surface area perpendicular to the line of action of that force is given by the formula

P = (F/A)

where F = applied force, in this case, water pressure force on the window = ?

A = Area upon which the force is acting = Area of the window = 0.3 m²

P = 500 kPa = 500,000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

Hope this Helps!!!

6 0

2 years ago