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I am Lyosha [343]
2 years ago
9

Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground. What is the approxi

mate horizontal component of the initial velocity?
Physics
2 answers:
AleksandrR [38]2 years ago
7 0
The horizontal component is calculated as:
Vhorizontal = V · cos(angle)

In your case Vhoriontal = 16 · cos(40) = 12.3 m/s

Answer: 12.3 m/s
marysya [2.9K]2 years ago
4 0

Answer:

Answer:D 12.3 m/s

Explanation:

I just took the quiz

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(a) A 15.0 kg block is released from rest at point A in the figure below. The track is frictionless except for the portion betwe
castortr0y [4]

Answer:

(a) coefficient of friction = 0.451

This was calculated by the application of energy conservation principle (the total sum of energy in a closed system is conserved)

(b) No, it comes to a stop 5.35m short of point B. This is so because the spring on expanding only does a work of 43 J on the block which is not enough to meet up the workdone of 398 J against friction.

Explanation:

The detailed step by step solution to this problems can be found in the attachment below. The solution for part (a) was divided into two: the motion of the body from point A to point B and from point B to point C. The total energy in the system is gotten from the initial gravitational potential energy. This energy becomes transformed into the work done against friction and the work done in compression the spring. A work of 398J was done in overcoming friction over a distance of 6.00m. The energy used in doing so is lost as friction is not a conservative force. This leaves only 43J of energy which compresses the spring. On expansion the spring does a work of 43J back on the block is only enough to push it over a distance of 0.65m stopping short of 5.35m from point B.

Thank you for reading and I hope this is helpful to you.

4 0
2 years ago
It has been proposed that extending a long conducting wire from a spacecraft (a "tether") could be used for a variety of applica
denis23 [38]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The angle between shuttle's velocity and the Earth's field is  \theta =   24.2^o

Explanation:

From the question we are told that

     The length of eire let out is  L = 250 \ m

      The emf generated is \epsilon = 40 V

      The earth magnetic field is B = 5.0 *10^{-5} T

     The speed of the shuttle and tether is v =  7.80 * 10^3 \  m/s

The emf generated is mathematically represented as

                             \epsilon = L\ v\ B\ sin \ \theta

making \theta  the subject of the formula

                        \theta =   sin ^{-1}[ \frac{\epsilon}{L  * B  *v} ]

substituting values

                        \theta =   sin ^{-1}[ \frac{40}{250  * (5*10^{-5})  *(7.80 *10^{3})} ]

                        \theta =   24.2^o

6 0
2 years ago
Compressional stress on rock can cause strong and deep earthquakes, usually at _____.
valentinak56 [21]
The answer is reverse faults. 
7 0
2 years ago
Find the average power Pavg created by the force F in terms of the average speed vavg of the sled.
Katena32 [7]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

The power created  is  P_{avg} =  F  *  v_{avg}

Explanation:

From the question we are told that

    The that the average power is  mathematically represented as

            P_{avg} =  \frac{W }{\Delta  t  }

Where W is  is the Workdone which is  mathematically represented as

         W =  F  *  s

      Where F is  the applies force and  s  is the displacement  due to the force  

        So  

                P_{avg} =  \frac{F *s  }{\Delta  t  }

Now this  displacement can be represented mathematically as  

            s =  v_{avg} *  \Delta  t

Where v_{avg } is the average  velocity and \Delta  t is the time  taken  

So  

            P_{avg} =  \frac{F *v_{avg} *  \Delta  t    }{\Delta  t  }

=>         P_{avg} =  F  *  v_{avg}

3 0
2 years ago
The image on the left shows the charges on a balloon after it’s been rubbed with a wool cloth. The image on the right is a piece
taurus [48]

When wool is rubbed with a balloon, the wool is left with a positive charge as electrons have travelled from the wool to the balloon which means the balloon now has a negative charge.

Now that the balloon has a negative charge, you need to know:
The tissue paper originally contains electrons and protons
The fact that the balloon has a negative charge, it will ATTRACT protons because protons are POSITIVE and electrons are NEGATIVE.
So once they are attracted, they will move closer to one another.
3 0
2 years ago
Read 2 more answers
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