Explanation:
3
i believe that they are all going at 3.2 meters each, I did 4 times 0.8
Ordinary cells can convert chemical energy to electrical energy only, but rechargeable cells can also store electrical energy into chemical energy and vice versa. You will study more about it in your higher classes. secondary cells can be recharged and used again but dry cells cannot be recharged.
<u>Answer:</u>
Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.
<u>Explanation:</u>
Let the east point towards positive X-axis and north point towards positive Y-axis.
Speed of truck = 25 m/s north = 25 j m/s
Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s
= (1.43 i + 1.00 j) m/s
Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j
Magnitude of velocity = 26.04 m/s
Angle from positive horizontal axis = 86.85⁰
So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.
Answer:
Explanation:
It is given that,
Mass of the puck, m = 4.8 kg
Initial velocity of the puck, 
After 8 seconds, final velocity of the puck, 
Let the x and y component of force is given by 
.
x component of force is given by :
y component of force is given by :
So, the component of the force is . Hence, this is the required solution.
Divide the force given by mass and you will find the acceleration of the object :-
F = m × a
3.63 = 18.15 × a
3.63 = 18.15a
a = 3.63/18.15
a = 0.2 m/s^2
hope it helps!
