Which correctly identifies the parts of a transverse wave? A: crest B: amplitude C: wavelength D: trough A: trough B: amplitude
C: crest D: wavelength A: trough B: amplitude C: wavelength D: crest A: crest B: amplitude C: trough D: wavelength
2 answers:
Explanation :
In transverse waves the particles are oscillating perpendicular to the direction of propagation of waves.
The uppermost part of the wave is crests and the lowermost part is troughs.
Wavelength of a transverse wave is defined as the distance between two consecutive crests or troughs.
Amplitude is the maximum distance or displacement covered by a wave.
So, crest, amplitude, trough and wavelength identifies the parts of a transverse wave.
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a) The acceleration of the objects is
b) The tension in the string is 280.8 N
Explanation:
a)
We start by writing the equations of motion for the two masses attached to the pulley.
For the heavier mass, we have:
(1)
where
is the mass
is the acceleration of gravity
T is the tension in the string
a is the acceleration of the system (here we assumed that the heavier mass accelerates downward)
For the lighter mass, we have
(2)
where
T is the tension in the string
is the mass
is the acceleration of gravity
a is the acceleration of the system (here we assumed that the lighter mass accelerates upward)
From (1) we get
And substituting into (2),
b)
From the previous part of the problem we got an expression for the tension in the string:
Where we have
is the acceleration, found in part a)
Susbtituting, we find
Learn more about forces and acceleration:
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Answer:
The distance between the places where the intensity is zero due to the double slit effect is 15 mm.
Explanation:
Given that,
Distance between the slits = 0.04 mm
Width = 0.01 mm
Distance between the slits and screen = 1 m
Wavelength = 600 nm
We need to calculate the distance between the places where the intensity is zero due to the double slit effect
For constructive fringe
First minima from center
Second minima from center
The distance between the places where the intensity is zero due to the double slit effect
Put the value into the formula
Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.