Which correctly identifies the parts of a transverse wave? A: crest B: amplitude C: wavelength D: trough A: trough B: amplitude
C: crest D: wavelength A: trough B: amplitude C: wavelength D: crest A: crest B: amplitude C: trough D: wavelength
2 answers:
Explanation :
In transverse waves the particles are oscillating perpendicular to the direction of propagation of waves.
The uppermost part of the wave is crests and the lowermost part is troughs.
Wavelength of a transverse wave is defined as the distance between two consecutive crests or troughs.
Amplitude is the maximum distance or displacement covered by a wave.
So, crest, amplitude, trough and wavelength identifies the parts of a transverse wave.
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Answer:
a. Springs oscillate with the same frequency
Explanation:
As they both are in the same height at equilibrium, so
weight of ball must be balanced with spring force, that is
k×x=mg
k= stiffness constant of spring
x=distance stretched
g= acceleration due to gravity
so, we can write
k/m=g/x
as the g is a constant and they stretched to same distance x so the g/x term becomes constant and
and k/m is same for both the springs so they will oscillate at the same frequency.
hence option a is correct.
To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.
Where
A = Cross-sectional Area
Y = Young's modulus
= Coefficient of linear expansion for steel
= Temperature Raise
Our values are given as,
Replacing we have,
Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N