answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
melisa1 [442]
1 year ago
10

Which correctly identifies the parts of a transverse wave? A: crest B: amplitude C: wavelength D: trough A: trough B: amplitude

C: crest D: wavelength A: trough B: amplitude C: wavelength D: crest A: crest B: amplitude C: trough D: wavelength

Physics
2 answers:
jenyasd209 [6]1 year ago
9 0

Explanation :

In transverse waves the particles are oscillating perpendicular to the direction of propagation of waves.

The uppermost part of the wave is crests and the lowermost part is troughs.

Wavelength of a transverse wave is defined as the distance between two consecutive crests or troughs.

Amplitude is the maximum distance or displacement covered by a wave.

So, crest, amplitude, trough and wavelength identifies the parts of a transverse wave.

iVinArrow [24]1 year ago
8 0

Label B is the trough or lowest point of the wave

You might be interested in
A light bulb in a battery powered desk lamp has a current of 0.042 A and is connected to a 9.2 V battery. What is the resistance
12345 [234]

Answer:

A

Explanation:

4 0
1 year ago
Read 2 more answers
Suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
EleoNora [17]
Newton's second law ...Force = momentum change/time.momentum change = Forcextme.also, F=ma -> a=F/m - the more familiar form of Newton's second law
using one of the kinematic equations for m ...  V=u+at; u=0; a=F/m -> V=(F/m)xt.-> t=mV/F using one of the kinematic equations for 2m ... V=u+at; u=0; a=F/2m -> V=(F/2m)xt. -> t=2mV/F (twice as long, maybe ?)
I think I've made a mistake somewhere below, but I think that the principle is right ...using one of the kinematic equations for m ...  s=ut + (1/2)at^2); s=d;u=0;a=F/m; t=1;  -> d=(1/2)(F/m)=F/2musing one of the kinematic equations for 2m ...  s=ut + (1/2)at^2); s=d;u=0;a=F/2m; t=1;  -> d=(1/2)(F/2m)=F/4m (half as far ????? WHAT ???)
3 0
1 year ago
Read 2 more answers
Inna Hurry is traveling at 6.8 m/s, when she realizes she is late for an appointment. She accelerates at 4.5 m/s^2 for 3.2 s. Wh
Alborosie

Answer:

1) v = 21.2 m/s

2) S = 63.33 m

3) s = 61.257 m

4) Deceleration, a = -4.32 m/s²

Explanation:

1) Given,

The initial velocity of Inna, u = 6.8 m/s

The acceleration of Inna, a = 4.5 m/s²

The time of travel, t = 3.2 s

Using the first equation of motion, the final velocity is

                v = u + at

                   = 6.8 + 4.5 x 3.2

                   = 21.2 m/s

The final velocity of Inna is, v = 21.2 m/s

2) Given,

The initial velocity of Lisa, u = 12 m/s

The final velocity of Lisa, v = 26 m/s

The acceleration of Lisa, a = 4.2 m/s²

Using the III equations of motion, the displacement is

                          v² = u² +2aS

                         S = (v² - u²) / 2a

                            = (26² -12²) / 2 x 4.2

                            = 63.33 m

The distance Lisa traveled, S = 63.33 m

3) Given,

The initial velocity of Ed, u = 38.2 m/s

The deceleration of Ed, d = - 8.6 m/s²

The time of travel, t = 2.1 s

Using the II equations of motion, the displacement is

                        s = ut + 1/2 at²

                           =38.2 x 2.1 + 0.5 x(-8.6) x 2.1²

                           = 61.257 m

Therefore, the distance traveled by Ed, s = 61.257 m

4) Given,

The initial velocity of the car, u = 24.2 m/s

The final velocity of the car, v = 11.9 m/s

The time taken by the car is, t = 2.85 s

Using the first equations of motion,

                         v = u + at

∴                        a = (v - u) / t

                            = (11.9 - 24.2) / 2.85

                            = -4.32 m/s²

Hence, the deceleration of the car, a = = -4.32 m/s²

5 0
1 year ago
Read 2 more answers
A teacher sets up a stand carrying a convex lens of focal length 15 cm at 20.5 cm mark on the optical bench. She asks the studen
Brums [2.3K]
We get the clearest image if there is no magnification. When we have no magnification the image and real object have the same size.
If we look at the diagram that I  attached we can see that:
\frac{h_i}{h_0}=\frac{d_i}{d_0}
Two triangles that I marked are similar and from this we get:
\frac{h_i}{h_0}=\frac{d_i-f}{f}
The image and the object must have the same height so we get:
\frac{h_i}{h_0}=\frac{d_i-f}{f};h_i=h_0\\
1=\frac{d_i-f}{f}\\
d_i=2f
This tells how far the screen should be from the lens. 
The position of the screen on the optical bench is:
S=20.5cm+2f=20.5+2\cdot 15cm=50.5cm

8 0
1 year ago
"In analyzing distances by apply ing the physics of gravitational forces, an astronomer has obtained the expression
zavuch27 [327]

Answer:

The value of R is 1.72\times10^{11}\ m.

(B) is correct option.

Explanation:

Given that,

In analyzing distances by apply ing the physics of gravitational forces, an astronomer has obtained the expression

R=\sqrt{\dfrac{1}{(\dfrac{1}{140\times10^{9}})^2-(\dfrac{1}{208\times10^{9}})^2}}

We need to calculate this for value of R

R=\sqrt{\dfrac{1}{(\dfrac{1}{140\times10^{9}})^2-(\dfrac{1}{208\times10^{9}})^2}}

R=1.89\times10^{11}\ m

So, The nearest option of the value of R is 1.72\times10^{11}\ m

Hence, The value of R is 1.72\times10^{11}\ m.

6 0
2 years ago
Other questions:
  • A Styrofoam slab has thickness h and density ρs. When a swimmer of mass m is resting on it, the slab floats in fresh water with
    5·1 answer
  • HURRY UP PLZZZ Two identical waves are traveling toward each other in the same medium. One has a positive amplitude, meaning tha
    14·2 answers
  • The famous leaning tower of pisa doesn't topple over because its center of gravity is
    14·1 answer
  • Which of the following statements characterizing types of waves are true?
    5·1 answer
  • A solenoid of length 0.700m having a circular cross-section of radius 5.00cm stores 6.00 μJ of energy when a 0.400-A current run
    10·2 answers
  • What speed would a fly with a mass of 0.55g need in order to have a kinetic energy of 7.6 •10^4 j?
    12·1 answer
  • The wad of clay of mass m = 0.36 kg is initially moving with a horizontal velocity v1 = 6.0 m/s when it strikes and sticks to th
    7·1 answer
  • Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =
    11·1 answer
  • A student has made the statement that the electric flux through one half of a Gaussian surface is always equal and opposite to t
    13·1 answer
  • What are the reasons for the establishment of UGA?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!