Answer:
40m approximately
Explanation:
Given
Force =377N
Mass =86.5kg
Velocity =13.2m/s
Required
Radius of the track
The expression for the centripetal force acting on the cyclist is
F=mv²/r
Make r subject of the formula
r= mv²/F
Substitute
r=86.5*13.2²/377
r= 15,071.76/377
r=39.97
r=40m approximately
Answer:
50.0543248872 ft
Explanation:
F = Load = 20 ton = 
d = Diameter = 1.25 in
= Initial length = 50 ft
= Final length
A = Area = 
Y = Young's modulus = 
Young's modulus is given by

The length during the lift is 50.0543248872 ft
Answer:
T = g μ_s ( M+m )
78.4 N
Explanation:
When both of them move with the same acceleration , small box will not slip over the bigger one. When we apply force on the lower box, it starts moving with respect to lower box. So a frictional force arises on the lower box which helps it too to go ahead . The maximum value that this force can attain is mg μ_s . As a reaction of this force, another force acts on the lower box in opposite direction .
Net force on the lower box
= T - mg μ_s = M a ( a is the acceleration created by net force in M )
Considering force on the upper box
mg μ_s = ma
a = g μ_s
Put this value of a in the equation above
T - m gμ_s = M g μ_s
T = mg μ_s + M g μ_s
= g μ_s ( M+m )
2 )
Largest tension required
T = 9.8 x .50 x ( 10+6 )
= 78.4 N
Potential Energy = mass * Hight * acceleration of gravity
PE=hmg
PE = 1.5 * .2 * 9.81
PE = 2.943
it lost .6 so 2.943 - .6 = 2.343
now your new energy is 2.343 so solve for height
2.343 = mhg
2.334 = .2 * h * 9.81
h = 1.194
the ball after the bounce only went up 1.194m
Answer: One canister contains 1.03 Kg of fuel,
Explanation:
The density is defined as the relation between the mass and the volume 
First of all you need to have the same units for volume and density, so:
For the volume,

For the density,

From the density equation we have
, so:
