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Lapatulllka [165]
2 years ago
7

A container of volume 0.6 m^3 contains 5.3 mol of argon gas at 24°C. Assuming argon behaves as an ideal gas, find the total inte

rnal energy of this gas. The value of the gas constant is 8.31451 J/mol * K. Answer in units of J.
Physics
1 answer:
Vitek1552 [10]2 years ago
5 0

Answer:

the internal energy of the gas is 433089.52 J

Explanation:

let n be the number of moles, R be the gas constant and T be the temperature in Kelvins.

the internal energy of an ideal gas is given by:

Ein = 3/2×n×R×T

     = 3/2×(5.3)×(8.31451)×(24 + 273)

     = 433089.52 J

Therefore, the internal energy of this gas is 433089.52 J.

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Air escapes from a balloon at a rate of 2 60 ( ) 1 R t t   3 ft / min , where t is measured in minutes. How much air (in 3 ft
kotykmax [81]

Answer:

Given R (t) = 60/(1+t²), ft /min

To find the amount of air in ft³, during the first min,

R (t) = 60/(1+t²

at t=1min, R is the air amount in ft³/min

Take the integral, and evaluate over [0,1]

Integral Of R (t) = 60/(1+t²) = 60 tan⁻¹(t),

60(Tan⁻¹(1) - Tan⁻¹(0)) = 60(pi/2) = 30 π

Therefore, it means that in the first minute, 30π ft³ of air escaped.

4 0
2 years ago
A spaceship which is 50,000 kilometers from the center of Earth has a mass of 3,000 kilograms. What is the magnitude of the forc
Anna11 [10]
Fg=Gx(M1M2/r^2)
Fg=478N
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2 years ago
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A spherical balloon is 40 ft in diameter and surrounded by air at 60°F and 29.92 in Hg abs.(a) If the balloon is filled with hyd
masha68 [24]
It's obviously b because the more helium it has, the lighter it is...
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2 years ago
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Suppose an acorn with a mass of 3.17 g falls off a tree. At a particular moment during the fall, the acorn has a kinetic energy
8090 [49]

Answer:

potential energy decrease and kinetic energy increases.

Explanation:

the law of conservation of energy says that the total energy of a system is conserved, then:

E_ki +E_pi = E_kf+E_pf

where E_{ki} is the initial kinetic energy, E_{pi} is the initial potential energy, E_{kf} is the final kinetic energy and E_{pf} is the final potential energy.

so, when the acorn fall the final potential energy is going to decrease because the potential energy is equal to:

E_p = mgh

Where m is the mass, g the gravity and h the height.

Therefore, in order to fullfil with the law of conservation of energy is necesary that the final kinetic energy increase.

Now, we know that the kinetic energy is equal to:

E_k = \frac{1}{2}mv^2

where v is the velocity, so, it means that the velocity of the acorn is going to increase.      

4 0
2 years ago
A shift in one fringe in the Michelson-Morley experiment corresponds to a change in the round-trip travel time along one arm of
olya-2409 [2.1K]

Explanation:

When Michelson-Morley apparatus is turned through 90^{o} then position of two mirrors will be changed. The resultant path difference will be as follows.

      \frac{lv^{2}}{\lambda c^{2}} - (-\frac{lv^{2}}{\lambda c^{2}}) = \frac{2lv^{2}}{\lambda c^{2}}

Formula for change in fringe shift is as follows.

          n = \frac{2lv^{2}}{\lambda c^{2}}

       v^{2} = \frac{n \lambda c^{2}}{2l}

             v = \sqrt{\frac{n \lambda c^{2}}{2l}}

According to the given data change in fringe is n = 1. The data is Michelson and Morley experiment is as follows.

             l = 11 m

    \lambda = 5.9 \times 10^{-7} m

           c = 3.0 \times 10^{8} m/s

Hence, putting the given values into the above formula as follows.

            v = \sqrt{\frac{n \lambda c^{2}}{2l}}

               = \sqrt{\frac{1 \times (5.9 \times 10^{-7} m) \times (3.0 \times 10^{8})^{2}}{2 \times 11 m}}

               = 2.41363 \times 10^{9} m/s

Thus, we can conclude that velocity deduced is 2.41363 \times 10^{9} m/s.

3 0
2 years ago
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