A container of volume 0.6 m^3 contains 5.3 mol of argon gas at 24°C. Assuming argon behaves as an ideal gas, find the total inte
1 answer:
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Answer:
Explanation:
According to the newton's second law of motion we can apply F=ma hear
Force = mass * acceleration
(assume the piano is moving left side )
←F = ma
Answer:
(D) 96 kg-m/s
Explanation:
Let's start off by first calculating the normal force between the box and the floor.
This will be:
Normal Force = 12 * 9.81 = 117.72 N
We can now use the friction equation to find the frictional force on the box when it is moving:
Frictional force = Coefficient of friction * Normal Force
Frictional force = 0.4 * 117.72 = 47.09 N
Finally, since we have the force on the box, we can find the acceleration:
F = Mass * Acceleration
47.09 = 12 * Acceleration
Acceleration = 3.92 m/s^2
Final speed after 2 seconds:
V= -3.84 m/s
Since we know the initial and final speeds, we can calculate the change in momentum:
Change in momentum = Final Momentum - Initial Momentum
Change in momentum =
Change in momentum = 94.08 kg*m/s
Thus we can see that option (D) is the closest answer.
Answer:
Mass, m = 2.2 kg
Explanation:
It is given that,
Frequency of the piano, f = 440 Hz
Length of the piano, L = 38.9 cm = 0.389 m
Tension in the spring, T = 667 N
The frequency in the spring is given by :
is the linear mass density
On rearranging, we get the value of m as follows :
m = 0.0022 kg
or
m = 2.2 grams
So, the mass of the object is 2.2 grams. Hence, this is the required solution.
Answer:
230
Explanation:
= Rotational speed = 3600 rad/s
I = Moment of inertia = 6 kgm²
m = Mass of flywheel = 1500 kg
v = Velocity = 15 m/s
The kinetic energy of flywheel is given by
Energy used in one acceleration
Number of accelerations would be given by
So the number of complete accelerations is 230