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docker41 [41]
2 years ago
15

16) A wheel of moment of inertia of 5.00 kg-m2 starts from rest and accelerates under a constant torque of 3.00 N-m for 8.00 s.

What is the wheel's rotational kinetic energy at the end of 8.00 s?
Physics
2 answers:
KiRa [710]2 years ago
6 0

Answer:

57.6Joules

Explanation:

Rotational kinetic energy of a body can be determined using the expression

Rotational kinetic energy = 1/2Iω²where;

I is the moment of inertia around axis of rotation. = 5kgm/s²

ω is the angular velocity = ?

Note that torque (T) = I¶ where;

¶ is the angular acceleration.

I is the moment of inertia

¶ = T/I

¶ = 3.0/5.0

¶ = 0.6rad/s²

Angular acceleration (¶) = ∆ω/∆t

∆ω = ¶∆t

ω = 0.6×8

ω = 4.8rad/s

Therefore, rotational kinetic energy = 1/2×5×4.8²

= 5×4.8×2.4

= 57.6Joules

Readme [11.4K]2 years ago
4 0

Given Information:

Torque = τ =  3.0 N.m

Moment of inertia = I = 5.0 kg.m²

Time = t = 8 seconds

Required Information:

Rotational kinetic energy = Erot = ?

Answer:

Rotational kinetic energy = 57.6 Joules

Explanation:

We know that the rotational kinetic energy of the wheel is the energy due to its rotation and is part of its total kinetic energy and is given by

Erot = ½Iω²  

Where ω is the angular velocity and I is the moment of inertia of the wheel.

We also know the relation between torque and moment of inertia is

τ = Iα

Where α is the angular acceleration of the wheel.

α = τ/I

From the equations of kinematics, we know that final angular velocity is given by

ω = ω₀ + αt

Where ω₀ is the initial angular velocity of the wheel and since wheel starts from rest, ω₀ is zero.

ω = 0 + αt

ω = αt

ω = (τ/I)t

ω = τ*t/I

Finally the equation of rotational kinetic energy becomes

Erot = ½Iω²

Erot = ½I(τ*t/I)²

Erot = ½*5*((3*8)/5)²

Erot = ½*5*(23.04)

Erot = ½*(115.2)

Erot =   57.6 J

Therefore, the wheel's rotational kinetic energy at the end of 8 s is 57.6 Joules.

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Answer:

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R = V₀² Sin 2θ/g

(a)

For moon:

R = Range on moon = Rm

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θ = Launch Angle = 17°

g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²

Therefore,

Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)

<u>Rm = 268.4 m</u>

(b)

For Earth:

R = Range on Earth = Re

V₀ = Launch Speed = 28 m/s

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Therefore,

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A body covers a semicircle of radius 7cm in 5s .find its linear speed
choli [55]

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From the data we got we can calculate speed, frequency, perimeter and area of the semicircle.

Let's start with perimeter.

We know that perimeter of circle is 2\pi r so the perimeter of semicircle is \dfrac{2\pi r}{2} or simply \pi r

So the perimeter is equal to:

\pi r=\pi\cdot7\approx\boxed{22cm}

So this is the length of a curve or let's say the distance.

Now let's look at the linear speed s=\dfrac{d}{t} where d is distance and t time.

We know the distance and we know the time.

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Roman55 [17]

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The current has velocity vector (relative to the Earth)

\vec v_{W/E}=\left(3.0\dfrac{\rm km}{\rm h}\right)\,\vec\imath

The swimmer's resultant velocity (her velocity relative to the Earth) is then

\vec v_{S/E}=\vec v_{S/W}+\vec v_{W/E}

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Note: We do not need to worry about the signs, as everything is moving towards each other. If something/somebody were moving away, we would have the negative sign. However, in this problem it is not the issue.

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v_{s} = Velocity of the source with respect to medium = 0 m/s.
f_{o} =  Frequency emitted from source = 400 Hz.
f = Observed frequency = 408Hz.

Plug-in the above values in the equation (A), you would get:

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bulgar [2K]

Answer:

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We need to make a sketch of the seesaw and the loads acting over it.

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A logical intuition will give us the idea that the mother will be on the side of her son to make the balance.

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Therefore the other loads ( mom + son) must be create a momentum equal to the maximum momentum.

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