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Mademuasel [1]
2 years ago
13

What body in the solar system do you think is one focus of the moons orbit

Physics
2 answers:
PolarNik [594]2 years ago
6 0

-- From the point of view of an observer on Earth, the moon's orbit is an ellipse
with the Earth's center at one focus.

-- From the point of view of an observer on the sun, or on any other planet,
the moon's orbit is an ellipse with the sun at one focus, and perturbed by being
near the Earth.


stiks02 [169]2 years ago
6 0
The Earth.

Orbits are elliptical in shape with the body being orbited at one focus. So the Sun is at one focus of the Earth's orbit around it.
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A carmaker has designed a car that can reach a maximum acceleration of 12 meters per second the cars mass is 1515 assuming the s
Rudiy27
The answer is attached. Also, you should know that the unit for acceleration is m/s2 and for velocity it is m/s.

5 0
2 years ago
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You are at a stop light in your car, stuck behind a red light. Just before the light is supposed to change, a fire engine comes
nikdorinn [45]

Answer:

The frequency of the sound you will hear is 713.85 Hz

Explanation:

Given;

speed of your car, v_s = 85.0 km/h

frequency of the siren, f = 665 Hz

Speed of sound in air, v = 345 m/s

The frequency of the sound you hear, can be calculated as;

f' = f(\frac{v}{v-v_s})

Convert the speed of the car to m/s

85 \ km/h =\frac{85 \ km}{h} (\frac{1000\ m}{1 \ km})(\frac{1 \ h}{3600 \ s} ) = 23.61 \ m/s

f' = f(\frac{v}{v-v_s} )\\\\f' = 665(\frac{345}{345-23.61} )\\\\f' =  665 (1.07346)\\\\f' = 713.85 \ Hz

Therefore, the frequency of the sound you will hear is 713.85 Hz

7 0
2 years ago
Calculate the amount of energy produced in a nuclear reaction in which the mass defect is 0.187456 amu.
luda_lava [24]
For nuclear reactions, we determine the energy dissipated from the process from the Theory of relativity wherein energy is equal to the mass defect times the speed of light. We calculate as follows:

E = mc^2 = 0.187456 (3x10^8)^2 = 1.687x10^16 J

Hope this answers the question.
8 0
2 years ago
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Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc
xxMikexx [17]

Answer: 14.52*10^6 m/s

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the change in potential energy for the electron; e*ΔV is  equal to energy kinetic gained for the electron so:

e*ΔV=1/2*m*v^2  v^=(2*e*ΔV/m)^1/2= (2*1.6*10^-19*600/9.1*10^-31)^1/2=14.52 *10^6 m/s

3 0
2 years ago
A 5-kg concrete block is lowered with a downward acceleration of 2.8 m/s2 by means of a rope. The force of the block on the Eart
maksim [4K]

When the body touches the ground two types of Forces will be generated. The Force product of the weight and the Normal Force. This is basically explained in Newton's third law in which we have that for every action there must also be a reaction. If the Force of the weight is pointing towards the earth, the reaction Force of the block will be opposite, that is, upwards and will be equivalent to its weight:

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F = 5*9.8

F = 49N

Therefore the correct answer is E.

5 0
2 years ago
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