All categories

2 years ago

Now that economic times are bad, some people blame immigrants for taking jobs. This is an example of:

Physics

1 answer:

velikii [3]2 years ago

8 0

Answer:

A. Scapegoat theory

A P E X

Explanation:

It's the tendency to find a group on which to blame problems in order to divert attention away from one's own failings.

You might be interested in

A jogger runs 10.0 blocks do east, 5.0 blocks due South, and another two. Zero blocks do east. Assume all blocks are equal size,

Annette [7]

Jogger moves in three displacements

d1 = 10 blocks East

d2 = 5 blocks South

d3 = 2 blocks East

now we can say

total displacement towards East direction will be

$d_x = 10 + 2= 12 blocks$

Total displacement towards South

$d_y = 5 block$

now to find the net displacement we can use vector addition

$d = \sqrt{d_x^2 + d_y^2}$

$d = \sqrt{12^2 + 5^2}$

$d = 13 blocks$

<em>so magnitude of net displacement will be equal to 13 blocks</em>

6 0

1 year ago

An observer O is standing on a platform of length L = 90 m on a station. A rocket train passes at a relative (constant) speed of

Natali [406]

Answer:

Explanation:

Since the front and back of the rocket simultaneously line up with forward and backward end of the platform respectively .

Then length of the platform = length of the train rocket .

A )

Time to cross a particular point on the platform

= length of rocket train / .96 x 3 x 10⁸

= 90 / .96 x 3 x 10⁸

= 31.25 x 10⁻⁸ s

B) Rest length of the rocket = length of platform = 90 m

C ) length of platform as viewed by moving observer =

$\frac{90}{\sqrt{1-\frac{v^2}{c^2 } } }$

= $\frac{90}{\sqrt{1-\frac{0.92}{1 } } }$

= 321 m

D ) For the observer on platform time taken = 31.25 x 10⁻⁸ s

for the observer in the rocket , time will be dilated so time recorded by observer in motion ,

$31.25\times10^{-8} \times \sqrt{1-\frac{.96^2}{1} }$

8.75 x 10⁻⁸ s .

8 0

1 year ago

A mass of 0.4 kg hangs motionless from a vertical spring whose length is 0.76 m and whose unstretched length is 0.41 m. Next the

Blizzard [7]

<h3><u>Answer;</u></h3>

= 1.256 m

<h3><u>Explanation;</u></h3>

We can start by finding the spring constant

F = k*y

Therefore; k = F/y = m*g/y

= 0.40kg*9.8m/s^2/(0.76 - 0.41)

= 11.2 N/m

Energy is conserved

Let A be the maximum displacement

Therefore; 1/2*k*A^2 = 1/2*k*(1.20 - 0.41)^2 + 1/2*m*v^2

Thus; A = sqrt((1.20 - 0.55)^2 + m/k*v^2)

= sqrt((1.20 -0.55)^2 + 0.40/9.8*1.6^2)

= 0.846 m

Thus; the length will be 0.41 + 0.846 = 1.256 m

6 0

2 years ago

The operator of a space station observes a space vehicle approaching at a constant speed v. The operator sends a light signal at

GenaCL600 [577]

Answer:

The speed of the light signal as viewed from the observer is c.

Explanation:

Recall the basic postulate of the theory of relativity that the speed of light is the same in ALL inertial frames. Based on this, the speed of light is independent of the motion of the observer.

5 0

2 years ago

A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly hori

Nutka1998 [239]

Answer:

The cannonball fly horizontally before it strikes the ground, S = 323.25 m

Explanation:

Given data,

The height of the cliff, h = 80 m

The horizontal velocity of the cannonball, Vₓ = 80 m/s

The range of the cannon ball with initial vertical velocity is zero is given by the formula,

$S=\frac{V_{x}\sqrt{2gh}}{g}$

$S=\frac{80\sqrt{2\times9.8\times80}}{9.8}$

S = 323.25 m

Hence, the cannonball fly horizontally before it strikes the ground, S = 323.25 m

7 0

2 years ago

Read 2 more answers