Question

A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly horizontal velocity of 80.0 M/S how far will the cannonball fly horizontally before it strikes the ground

Answer 1

Answer:

The cannonball fly horizontally before it strikes the ground, S = 323.25 m

Explanation:

Given data,

The height of the cliff, h = 80 m

The horizontal velocity of the cannonball, Vₓ = 80 m/s

The range of the cannon ball with initial vertical velocity is zero is given by the formula,

                           $S=\frac{V_{x}\sqrt{2gh}}{g}$

                           $S=\frac{80\sqrt{2\times9.8\times80}}{9.8}$

                           S = 323.25 m

Hence, the cannonball fly horizontally before it strikes the ground, S = 323.25 m

Answer 2

Answer:it’s 320

Explanation: