Question

If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the nearest watt?

Answer 1

Answer:

Output Power = 3 Watt

Explanation:

As we know that loss of 3 dB occurs when it is having input of 6 Watts

So here we can say that

$3 dB = 10 Log\frac{P_{in}}{P_{out}}$

now we know that

$P_{in} = 6 Watt$

so we will have

$0.30 = Log \frac{6}{P_{out}}$

now we have

$P_{out} = 6 \times 10^{-0.30}$

$P_{out} = 3 Watt$

So output power will be 3 Watt

Answer 2

Answer:

Output power of the circuit is 3 Watt.

Given:

loss in decibles = 3 dB

Input power = 6 Watt

To find:

Output power = ?

Formula used:

Output power = Input power × loss in ratio

Solution:

3 dB loss = 0.5 ratio

Output power is given by,

Output power = Input power × loss in ratio

Output power = 6 × 0.5

Output power = 3 Watt

Thus, output power of the circuit is 3 Watt.