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1 year ago

Shows an object suspended from two ropes. The weight of the object is 360 N. The magnitude of the tension

Physics

1 answer:

konstantin123 [22]1 year ago

6 0

Answer:

Tension T in each rope will be 254.56 N.

Explanation:

From the picture attached,

Weight suspended by the two ropes will be supported by the vertical components of the tension in the ropes.

Vertical components of both the ropes = Tsin(45)° + Tsin(45)°

= 2Tsin(45)°

= $2T(\frac{1}{\sqrt{2}})$

= $T\sqrt{2}$

Since, $T\sqrt{2}=360$

T = $\frac{360}{\sqrt{2} }$

T = 254.56 N

Therefore, tension T in each rope will be 254.56 N.

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In very cold weather, a significant mechanism for heat loss by the human body is energy expended in warming the air taken into t

Pie

Answer:

A) $Q_a=74256\ J$

B) $Q=93562560\ J$

Explanation:

Given:

temperature of air, $T_a=-19+273=254\ K$

temperature of lungs, $T_l=37+273=310\ K$

specific Heat exchanged from the lungs , $c_l=0.47\ J.kg^{-1}.K^{-1}$

specific heat of air, $c_a=1020\ J.kg^{-1}.K^{-1}$

mass of 1 L air, $m'=1.3\ kg$

breath rate, $b=21\ breath.min^{-1}$

Now,

amount of heat needed to warm the air of lungs to the body temperature:

$Q_a=m'.c_a.\Delta T$

$Q_a=1.3\times1020\times (310-254)$

$Q_a=74256\ J$

Amount of heat lost per hour:

<u>No. of breaths per hour:</u>

$B=b.60$

$B=21\times 60$

$B=1260$

<u>Now the total loss of energy in 1 hr.:</u>

$Q=Q_a.B$

$Q=74256\times 1260$

$Q=93562560\ J$

7 0

2 years ago

Tyson throws a shot put ball weighing 7.26 kg. At a height of 2.1 m above the ground, the mechanical energy of the ball is 172.1

nika2105 [10]

Answer:

Velocity, v = 2.50 m/s

Explanation:

Given that,

Mass of the ball, m = 7.26 kg

Height above the ground, h = 2.1 m

Mechanical energy of the ball, T = 172.1 J

To find,

The velocity of the ball at the given point.

Solution,

The sum of potential energy and the kinetic energy is called the mechanical energy of an object. It is given by :

$T=K+P$

K is the kinetic energy

P is the potential energy

$T=\dfrac{1}{2}mv^2+mgh$

On rearranging the above equation,

$v^2=\dfrac{2(T-mgh)}{m}$

$v^2=\dfrac{2(172.1-7.26\times 9.8\times 2.1)}{7.26}$

v = 2.50 meters

Therefore, the velocity of the ball at the given point is 2.50 m/s.

7 0

1 year ago

Read 2 more answers

A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits th

Reptile [31]

Initial speed of the coin (u)= 0 (As the coin is released from rest)

Acceleration due to gravity (a) = g = 9.81 m/s²

Time of fall (t) = 1.5 s

From equation of motion we have:

$\boxed{ \bf{v = u + at}}$

By substituting values in the equation, we get:

$\longrightarrow$ v = 0 + 9.81 × 1.5

$\longrightarrow$ v = 14.715 m/s

$\therefore$ Speed of the coin as it hits the ground/Final speed of the coin = 14.715 m/s

6 0

1 year ago

Lexy used the formula shown to calculate the force of gravity on a space shuttle. Fg = G What does 3 × 105 kg represent? the dif

STALIN [3.7K]

<h2>Answer:</h2>

<u>This term shows the </u><u>mass of the space shuttle</u>

<h2>Explanation:</h2>

We know that the mass of the Earth is 5.972 × 10^24 kg. Similarly the sum of mass of earth and the mass of shuttle must be a greater number as compared to the number given. It simply means that the mass of earth is itself 5.972 × 10^24 kg and the value given is 3 × 105 kg so it is obvious that if was the sum then it must be greater than the mass of earth. Therefore we can say that this not the mass of earth, neither the sum of mass of earth and shuttle, but this is only the mass of space shuttle which is the last multiple choice.

5 0

1 year ago

Hoosier Manufacturing operates a production shop that is designed to have the lowest unit production cost at an output rate of 1

abruzzese [7]

Answer:

90.77%

its capacity utilization rate for the month is 90.77%

Explanation:

The capacity utilisation rate can be expressed mathematically as;

Capacity utilisation rate = capacity used/Best operating level × 100%

Given;

Total Number of production time = 205hours

Production output/capacity used = 21400 units

Best operation rate = 115units/hour

Best operation output for the month of July( at best operation level )

=115units/hour × 205 hours = 23575 units

Capacity utilisation rate = 21400/23575 × 100%

= 90.77%

3 0

2 years ago