Question

Shows an object suspended from two ropes. The weight of the object is 360 N. The magnitude of the tension

Answer 1

Answer:

Tension T in each rope will be 254.56 N.

Explanation:

From the picture attached,

Weight suspended by the two ropes will be supported by the vertical components of the tension in the ropes.

Vertical components of both the ropes = Tsin(45)° + Tsin(45)°

                                                                 = 2Tsin(45)°

                                                                 = $2T(\frac{1}{\sqrt{2}})$

                                                                 = $T\sqrt{2}$

Since, $T\sqrt{2}=360$

T = $\frac{360}{\sqrt{2} }$

T = 254.56 N

Therefore, tension T in each rope will be 254.56 N.