The speed is 0.956 m / s.
<u>Explanation</u>:
The kinetic energy is equal to the product of half of an object's mass, and the square of the velocity.
K.E = 1/2
m

where K.E represents the kinetic energy,
m represents the mass,
v represents the velocity.
K.E = 1/2
m

1.10
10^42 = 1/2
3.26
10^31

= (1.10
10^42
2) / (3.26
10^31)
v = 0.956 m / s.
The force of friction is 19.1 N
Explanation:
According to Newton's second law, the net force acting on the bag is equal to the product between its mass and its acceleration:

where
is the net force
m is the mass
a is the acceleration
The bag is moving at constant speed, so its acceleration is zero:

Therefore the net force is zero as well:

Here we are interested only in the forces acting along the horizontal direction, therefore the net force is given by:

where
is the horizontal component of the applied force, with
F = 22.5 N

is the force of friction
And solving for
, we find

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Answer:
The charge on the dust particle is 
Explanation:
From the question we are told that
The length is 
The width is 
The charge is 
The mass suspended in mid-air is 
Generally the electric field on the carpet is mathematically represented as

Where
is the permittivity of free space with value 
substituting values


Generally the electric force keeping the dust particle on the air equal to the force of gravity acting on the particles

=> 
=> 
=> 
=> 
The acceleration of gravity on Moon B is D) 0.25 m/s2
Explanation:
The data listed in the problem are not clear: find them in the table attached.
The acceleration of gravity on a planet is given by the following equation:

where:
is the gravitational constant
M is the mass of the planet
R is the radius of the planet
Here we want to find the acceleration of gravity on the surface of Moon B, which has the following data:
(mass)
(radius)
And substituting into the equation, we find:

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Answer:
The essential matrix in this case is given by
![E=[T_{x}]R=\left[\begin{array}{ccc}0&0&0\\0&0&d\\0&-d&0\end{array}\right]](https://tex.z-dn.net/?f=E%3D%5BT_%7Bx%7D%5DR%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%260%5C%5C0%260%26d%5C%5C0%26-d%260%5Cend%7Barray%7D%5Cright%5D)
the values of the 3x3 essential matrix E for this stereo system
![E=[T_{x}]R=\left[\begin{array}{ccc}0&0&0\\0&0&0.12\\0&-0.12&0\end{array}\right]](https://tex.z-dn.net/?f=E%3D%5BT_%7Bx%7D%5DR%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%260%5C%5C0%260%260.12%5C%5C0%26-0.12%260%5Cend%7Barray%7D%5Cright%5D)
Explanation:
The explanation is shown on the first uploaded image