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kicyunya [14]
2 years ago
10

If two waves with identical crests and troughs meet, what is happening?

Physics
2 answers:
Vesna [10]2 years ago
4 0
<span>If two waves with identical crests and troughs meet, then we know
that they have the same amplitude, frequency, and wavelength. 
But we still don't know whether they are "in step" or not.

If their crests of both waves line up, then constructive interference
will occur.

If the crests of one wave line up with the troughs of the other wave,
then destructive interference will occur. </span>
Nastasia [14]2 years ago
3 0
<span>If two waves with identical crests and troughs meet, what is happening?
</span>C. Constructive interference is occurring. 
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If a sound with frequency fs is produced by a source traveling along a line with speed vs. If an observer is traveling with spee
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Answer:

457.81 Hz

Explanation:

From the question, it is stated that it is a question under Doppler effect.

As a result, we use this form

fo = (c + vo) / (c - vs) × fs

fo = observed frequency by observer =?

c = speed of sound = 332 m/s

vo = velocity of observer relative to source = 45 m/s

vs = velocity of source relative to observer = - 46 m/s ( it is taking a negative sign because the velocity of the source is in opposite direction to the observer).

fs = frequency of sound wave by source = 459 Hz

By substituting the the values to the equation, we have

fo = (332 + 45) / (332 - (-46)) × 459

fo = (377/ 332 + 46) × 459

fo = (377/ 378) × 459

fo = 0.9974 × 459

fo = 457.81 Hz

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2 years ago
Which of the following sketches represents a possible configuration for this problem?
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Where are the following sketches?
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WILL GIVE BRAINLIEST AND 100 POINTS! NEED THIS ASAP!
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A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c
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Answer:

E=\frac{\lambda}{2\pi r\epsilon_0}

Explanation:

We are given that

Linear charge density of wire=\lambda

Radius of hollow cylinder=R

Net linear charge density of cylinder=2\lambda

We have to find the expression for the magnitude of the electric field strength inside the cylinder r<R

By Gauss theorem

\oint E.dS=\frac{q}{\epsilon_0}

q=\lambda L

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Where surface area of cylinder=2\pi rL

E=\frac{\lambda}{2\pi r\epsilon_0}

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