Answer:a) 4+8+24=36
B) 1/4+1/8+1/24=10
C) yu will connect them in parallel connection.
D) you will connect two in parallel then the remaining one in series to the ons connected in parallel.
Explanation:
Answer:
1.32.225 N/C, direction is away from the point charge
2. 8.972*10^-12 C
3. the field is directed away from the axon
Explanation:
The electric field can be calculated as shown below:
E = k*|q|/r^2
Where:
E = electric field; k = 8.98755*10^9 N*m^2/C^2; r = distance between the measured field and point charge = 0.05 m; q = the point charge
For 0.100 m of the axon, the value of q is:
q = (5.6*10^11)*(+e)*(0.001)
+e = charge of an electron = 1.60217*10^-19 C
Thus:
q = (5.6*10^11)*(1.60217*10^-19)*(0.0001) = 8.972*10^-12 C
Therefore:
E = (8.98755*10^9)*(8.972*10^-12)/0.05^2 = 32.255 N/C
A positive point charge always produce an electric field that is directed away from the field while a negative point charge produces an electric field that is directed toward the field
Explanation:
(b) A uniform beam 150cm long weighs 3.5kg and
supported on knife-edges at its ends. The beam
supports a weight 7kg at a distance 30cm from
one end. Find the reactions of the supports.
Answer:
(a) Height is 4.47 m
(b) Height is 4.37 m
Solution:
As per the question:
Initial velocity of teh ball, 
Angle made by the ramp, 
Distance traveled by the ball on the ramp, d = 5.00 m
Now,
(a) At any point on the projectile before attaining maximum height, the velocity can be given by the eqn-3 of motion:
where
H = 
g = 
= 19.06 m/s
Now, maximum height attained is given by:
Height from the ground = 
(b) now, considering the coefficient of friction bhetween ramp and the ball, 
:
velocity can be given by the eqn-3 of motion:
= 18.7 m/s
Now, maximum height attained is given by:
Height from the ground = 
For astronomical objects, the time period can be calculated using:
T² = (4π²a³)/GM
where T is time in Earth years, a is distance in Astronomical units, M is solar mass (1 for the sun)
Thus,
T² = a³
a = ∛(29.46²)
a = 0.67 AU
1 AU = 1.496 × 10⁸ Km
0.67 * 1.496 × 10⁸ Km
= 1.43 × 10⁹ Km
