the electric force decreases because the distance has an indirect relationship to the force
Explanation:
The electric force between two objects is given by

where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the distance between the two objects
As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.
We actually don't need to know how far he/she is standing from the net, as we know that the ball reaches its maximum height (vertex) at the net. At the vertex, it's vertical velocity is 0, since it has stopped moving up and is about to come back down, and its displacement is 0.33m. So we use v² = u² + 2as (neat trick I discovered just then for typing the squared sign: hold down alt and type 0178 on ur numpad wtih numlock on!!!) ANYWAY....... We apply v² = u² + 2as in the y direction only. Ignore x direction.
IN Y DIRECTION: v² = u² + 2as 0 = u² - 2gh u = √(2gh) (Sub in values at the very end)
So that will be the velocity in the y direction only. But we're given the angle at which the ball is hit (3° to the horizontal). So to find the velocity (sum of the velocity in x and y direction on impact) we can use: sin 3° = opposite/hypotenuse = (velocity in y direction only) / (velocity) So rearranging, velocity = (velocity in y direction only) / sin 3° = √(2gh)/sin 3° = (√(2 x 9.8 x 0.33)) / sin 3° = 49 m/s at 3° to the horizontal (2 sig figs)
Answer:
The correct answer is c. When the balloon hits the ground, the rubber envelope stretches, storing elastic potential energy; this elastic potential energy is converted to the gravitational potentiaL
Explanation:
Let's analyze the situation of the globe
When it touches the ground, the part that is in contact decreases its velocity to zero, but the upper part of the ball continues to move, which creates that the molecules approach slightly, if we approximate the spring links, a repulsive force is created that after all the particles reach zero speed. The force of the springs moves the ball up until the force decreases to zero.
We can relate this force of Hooke with an elastic energy
This energy can be stored in the deformation of the system, as elastic potential energy, which is subsequently transformed into gravitational potential energy when the balloon is lifted.
The correct answer is c
Explanation:
Mass of the Earth is equal to,

Any number can be written in the form of scientific notation as :

m is the real number
n is any integer
Mass of the earth can be written in the form of scientific notation as :

Here,
m = 5.97
n = 24
Hence, this is the required solution.
Answer:
A) vertically upward
Explanation:
Since the tyre is rotating with uniform angular speed and moving with constant linear speed
So as soon as a small stone is stuck into the groove of the tyre the speed of the stone is same as that of the tyre
so now we can say that stone will start revolving with the tyre of the car at constant angular speed and moving with uniform speed also
so here just after that the tangential acceleration of the stone must be zero while radial acceleration must be towards the center of the tyre given as

so we will have direction of net acceleration is towards its center so correct answer will be
A) vertically upward