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2 years ago

Use scientific (exponential) notation to express the following quantities in terms of the SI base units in

Physics

1 answer:

Anna007 [38]2 years ago

8 0

Answer:

When a number is written in scientific notation (representing the number using powers of base ten) it is expressed so that it contains a digit in the place of the units and all other digits after the decimal point, multiplied by the respective exponent. For example, the number $4.232(10)^{3}$ .

On the other hand, it is known the units in the SI for mass, length, time and temperature are kilogram (kg), meter (m), second (s) and Kelvin (K), respectively. In addition, thera are prefixes of the International System (SI) that indicate a specific factor of 10.

For example:

-Giga (G) is a prefix that indicates a factor of $10^{6}$

-Pico (p) is a prefix that indicates a factor of $10^{-12}$

-Mili (m) is a prefix that indicates a factor of $10^{-3}$

-Micro ( $\mu$ ) is a prefix that indicates a factor of $10^{-6}$

-Tera (T) is a prefix that indicates a factor of $10^{12}$

-Kilo (K) is a prefix that indicates a factor of $10^{3}$

Knowing this, let's express these quantities in terms of the SI base units:

$0.13 g=0.00013 kg=1.3 (10)^{-4}kg$

$232 Gg=232(10)^{6}g=232 (10)^{3}kg$

$5.23 pm=5.23(10)^{-12}m$

$86.3 mg=86.3(10)^{-3}g=8.63 (10)^{-5}kg$

$37.6 cm=0.376 m=3.76 (10)^{-1}m$

$54 \mu m=54 (10)^{-6}m$

$1 Ts=1 (10)^{-12}s$

$27 ps=27 (10)^{-12}s$

$0.15 mK=0.15(10)^{-3}K$

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Answer:

Part a)

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Part b)

$E = 8436.7 N/C$

Explanation:

Part a)

Electric field due to large sheet is given as

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$\sigma = \frac{Q}{A}$

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$\sigma = \frac{-3.8\times 10^{-9}}{0.025}$

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now the electric field is given as

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Part b)

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2 years ago

If a 10 meter ramp helps you move a 500 kg object up 1 meter. What was the mechanical advantage of the ramp?

sattari [20]

The mechanical advantage of an inclined plane is

(Length of the incline) / (its height)

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1 year ago

The current in a long solenoid of radius 6 cm and 17 turns/cm is varied with time at a rate of 5 A/s. A circular loop of wire of

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Answer:

53.63 μA

Explanation:

radius of solenoid, r = 6 cm

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n = 17 turns / cm = 1700 /m

di / dt = 5 A/s

The magnetic field due to the solenoid is given by

B = μ0 n i

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The rate of change in magnetic flux linked with the solenoid =

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= 3.14 x 64 x 10^-4 x 4 x 3.14 x 10^-7 x 1700 x 5 = 2.145 x 10^-4

The induced emf is given by the rate of change in magnetic flux linked with the coil.

e = 2.145 x 10^-4 V

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1 year ago

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Answer:

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1 year ago

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One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of ra

sveticcg [70]

Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

The radial acceleration ( $a_{r}$ ), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:

$a_{r} = 4\pi^{2}\cdot f^{2}\cdot R$ (1)

Where:

$f$ - Frequency, measured in hertz.

$R$ - Radius of rotation, measured in meters.

From Second Newton's Law, the centripetal acceleration is due to the existence of tension ( $T$ ), measured in newtons, through the string, then we derive the following model:

$\Sigma F = T = m\cdot a_{r}$ (2)

Where $m$ is the mass of the object, measured in kilograms.

By applying (1) in (2), we have the following formula:

$T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R$ (3)

From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

$\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right)$ (4)

$\frac{T_{2}}{T_{1}} = 4\cdot 2$

$\frac{T_{2}}{T_{1}} = 8$

If both the radius and frequency are doubled, then the tension is increased 8 times.

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1 year ago