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NemiM [27]
2 years ago
6

Use scientific (exponential) notation to express the following quantities in terms of the SI base units in

Physics
1 answer:
Anna007 [38]2 years ago
8 0

Answer:

When a number is written in scientific notation (representing the number using powers of base ten) it is expressed so that it contains a digit in the place of the units and all other digits after the decimal point, multiplied by the respective exponent.  For example, the number 4.232(10)^{3}.

On the other hand, it is known the units in the SI for mass, length, time and temperature are kilogram (kg), meter (m), second (s) and Kelvin (K), respectively. In addition, thera are prefixes of the International System (SI) that indicate a specific factor of 10.

For example:

-Giga (G) is a prefix that indicates a factor of 10^{6}

-Pico (p) is a prefix that indicates a factor of 10^{-12}

-Mili (m) is a prefix that indicates a factor of 10^{-3}

-Micro (\mu) is a prefix that indicates a factor of 10^{-6}

-Tera (T) is a prefix that indicates a factor of 10^{12}

-Kilo (K) is a prefix that indicates a factor of 10^{3}

Knowing this, let's express these quantities in terms of the SI base units:

0.13 g=0.00013 kg=1.3 (10)^{-4}kg

232 Gg=232(10)^{6}g=232 (10)^{3}kg

5.23 pm=5.23(10)^{-12}m

86.3 mg=86.3(10)^{-3}g=8.63 (10)^{-5}kg

37.6 cm=0.376 m=3.76 (10)^{-1}m

54 \mu m=54 (10)^{-6}m

1 Ts=1 (10)^{-12}s

27 ps=27 (10)^{-12}s

0.15 mK=0.15(10)^{-3}K

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An amusement park ride raises people high into the air, suspends them for a moment, and then drops them at a rate of free-fall a
blsea [12.9K]

Answer: apparent weighlessness.


Explanation:


1) Balance of forces on a person falling:


i) To answer this question we will deal with the assumption of non-drag force (abscence of air).


ii) When a person is dropped, and there is not air resistance, the only force acting on the person's body is the Earth's gravitational attraction (downward), which is the responsible for the gravitational acceleration (around 9.8 m/s²).


iii) Under that sceneraio, there is not normal force acting on the person (the normal force is the force that the floor or a chair exerts on a body to balance the gravitational force when the body is on it).


2) This is, the person does not feel a pressure upward, which is he/she does not feel the weight: freefalling is a situation of apparent weigthlessness.


3) True weightlessness is when the object is in a place where there exists not grativational acceleration: for example a point between two planes where the grativational forces are equal in magnitude but opposing in direction and so they cancel each other.


Therefore, you conclude that, assuming no air resistance, a person in this ride experiencing apparent weightlessness.

3 0
2 years ago
Read 2 more answers
Combine Newton's 2nd law and Hooke's law for a spring to find the acceleration of the block a(t) as a function of time. Express
Inga [223]

Answer:

a=-\dfrac{k}{m}x(t)

Explanation:

From Newton's second law,

F = ma

where F is the force, m is the mass and a is the acceleration.

From Hooke's law,

F = -kx(t)

where k is the spring constant and x(t) is the displacement function measured from the origin. The negative sign indicates the force acts in opposite direction to the displacement. In fact, it is a restoring force; it acts to return the spring to its original undisturbed position.

Since both forces are the same,

F = ma= - kx(t)

a=-\dfrac{k}{m}x(t)

The implication of this is that the acceleration is proportional to the displacement but opposite to it. That last statement is the definition of a simple harmonic motion which this is.

The ratio \dfrac{k}{m} is a constant except in situations where the mass is varying (say, the mass on the spring is a decaying material).

4 0
2 years ago
(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i
ddd [48]

Answer:

a) P = 370.993\,kPa, b) F = 25.948\,kN

Explanation:

a) The absolute pressure at a depth of 27.5 meters is:

P = P_{atm} + P_{man}

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (27.5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

P = 370.993\,kPa

b) The force exerted by the water is:

F = (P - P_{atm})\cdot A

F = (370.993\,kPa-101.3\,kPa)\cdot \left(\frac{\pi}{4} \right)\cdot (0.35\,m)^{2}

F = 25.948\,kN

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2 years ago
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DerKrebs [107]

Correct answer choice is :


C) A jar with snails crawling on living plants


Explanation:


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