Answer:
A) vertically upward
Explanation:
Since the tyre is rotating with uniform angular speed and moving with constant linear speed
So as soon as a small stone is stuck into the groove of the tyre the speed of the stone is same as that of the tyre
so now we can say that stone will start revolving with the tyre of the car at constant angular speed and moving with uniform speed also
so here just after that the tangential acceleration of the stone must be zero while radial acceleration must be towards the center of the tyre given as
so we will have direction of net acceleration is towards its center so correct answer will be
A) vertically upward
Answer:
The inducerd emf is 1.08 V
Solution:
As per the question:
Altitude of the satellite, H = 400 km
Length of the antenna, l = 1.76 m
Magnetic field, B = 
Now,
When a conducting rod moves in a uniform magnetic field linearly with velocity, v, then the potential difference due to its motion is given by:
Here, velocity v is perpendicular to the rod
Thus
e = lvB (1)
For the orbital velocity of the satellite at an altitude, H:
where
G = Gravitational constant
= mass of earth
= radius of earth
Using this value value in eqn (1):
Answer:
5.22 x 10^5 V
Explanation:
guessed on castle learning and got it right
<h2>The K.E of the charge is 1.02 x 10⁻¹⁷ J</h2>
Explanation:
When the charge of 2e is placed in between the plates .
The force applied on this charge by plates is = q E
here q is the magnitude of charge = 2 e = 2 x 1.6 x 10⁻¹⁹ C
and E is the magnitude of electric field intensity
The work done = Force x displacement
Thus W = q E x S
here S is displacement
Therefore W = 2 x 1.6 x 10⁻¹⁹ x 4 x 8
= 1.02 x 10⁻¹⁷ J
This work will be converted into the kinetic energy of charge .
Thus K.E = 1.02 x 10⁻¹⁷ J
A. a<span> = 1.3 m/s^2</span><span>; </span>FN<span> = 63.1 N</span>
