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NNADVOKAT [17]
1 year ago
8

Three flat layers of transparent material are stacked upon one another. The top layer has index of refraction n1, the middle has

n2 and the bottom one has n3. If n1 > n2 > n3, and if a ray of light strikes the top layer at an angle of incidence, in which layer is the angle of refraction the greatest? Why?
a. the bottom layer
b. the top layer
c. Once the ray enters the touching layers, the angle of refraction remains constant.
d. the middle layer

Physics
1 answer:
serg [7]1 year ago
7 0

Answer:

a. the bottom medium

Explanation:

it has the least index of refraction and hence most rarer.

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A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of
GREYUIT [131]

Answer:

a=190\ m/s^2

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2

So, the acceleration of the hockey puck is 190\ m/s^2.

5 0
2 years ago
A 3.0-kg brick rests on a perfectly smooth ramp inclined at 34° above the horizontal. The brick is kept from sliding down the pl
Firdavs [7]

Answer:

d=0.137 m ⇒13.7 cm

Explanation:

Given data

m (Mass)=3.0 kg

α(incline) =34°

Spring Constant (force constant)=120 N/m

d (distance)=?

Solution

F=mg

F=(3.0)(9.8)

F=29.4 N

As we also know that

Force parallel to the incline=FSinα

F=29.4×Sin(34)

F=16.44 N

d(distance)=F/Spring Constant

d(distance)=16.44/120

d(distance)=0.137 m ⇒13.7 cm

4 0
2 years ago
A) The current theory of the structure of the Earth, called plate tectonics, tells us that the continents are in constant motion
suter [353]

A) The mass of the continent is 2.5\cdot 10^{21} kg

B) The kinetic energy is 2016 J

C) The speed of the jogger should be 7.1 m/s

Explanation:

A)

The mass of the continent can be calculated as

m = \rho V

where

\rho = 2800 kg/m^3 is its density

V is its volume

We have to calculate its volume. We know that the continent is represented as a slab of side 5900 km (so its surface is 5900 x 5900, assuming it is a square) and depth of 26 km, so its volume is:

V=(5900 km)^2 (26 km)=9.05\cdot 10^8 km^3 =9.05 \cdot 10^8 \cdot (10^9 m^3/k^3)=9.05\cdot 10^7 m^3

So, the mass of the continent is

m=\rho V = (2800)(9.05\cdot 10^{17})=2.5\cdot 10^{21} kg

B)

The kinetic energy of a body is given by

K=\frac{1}{2}mv^2

where

m is the mass of the body

v is its speed

For the continent, we have:

m=2.5\cdot 10^{21} kg is the mass

v=4 cm/year is the speed

We have to convert the speed into SI units. we have:

1 cm = 0.01 m

1 year = (365)(24)(60)(60) s = 3.15\cdot 10^7 s

So, the speed is

v=4 cm/year = 0.04 m/year \cdot \frac{1}{3.15\cdot 10^7}=1.27\cdot 10^{-9} m/s

Therefore, the kinetic energy is

K=\frac{1}{2}(2.5\cdot 10^{21} kg)(1.27\cdot 10^{-9} m/s)^2=2016 J

C)

Again, the kinetic energy of an object is

K=\frac{1}{2}mv^2

For the jogger in this problem, his mass is

m = 80 kg

And we want its kinetic energy to be equal to that of the continent, so

K = 2016 J

Re-arranging the equation for v, we find what speed the jogger needs to have this kinetic energy:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(2016)}{80}}=7.1 m/s

Learn more about kinetic energy here:

brainly.com/question/6536722

#LearnwithBrainly

8 0
1 year ago
Mr. Smith is designing a race where velocity will be measured. Which course would allow velocity to accurately get a winner?
liraira [26]
I’m not completely sure but most likely is is the 10 mile bike ride, I hope I can help! (:
6 0
2 years ago
Read 2 more answers
The net force on a boat causes it to accelerate at 1.55 m/s2. The mass of the boat is 215 kg. The same net force causes another
jekas [21]

Answer:

2666 kg

0.11567 m/s²

Explanation:

m = Mass of boat

a = Acceleration of boat

From Newton's second law

Force

F=ma\\\Rightarrow F=215\times 1.55\\\Rightarrow F=333.25\ N

Force on the first boat is 333.25 N

F=ma\\\Rightarrow m=\frac{F}{a}\\\Rightarrow m=\frac{333.25}{0.125}\\\Rightarrow m=2666\ kg

Hence, mass of the second boat is 2666 kg

Combined mass = 2666+215 = 2881 kg

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{333.25}{2881}\\\Rightarrow a=0.11567\ m/s^2

The acceleration on the combined mass is 0.11567 m/s²

6 0
2 years ago
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