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oee [108]
2 years ago
10

Suppose that a sound has initial intensity β1 measured in decibels. This sound now increases in intensity by a factor f. What is

the new level of sound β2?
Physics
1 answer:
topjm [15]2 years ago
4 0

Answer:

β2= β1+10*f

Explanation:

comparing β2 and β1, it is said that β2 is increased by a factor of f.

for each factor of f, there is a 10*f dB increase.

therefore if the β1 is increases by an intensity of factor f

the new intensity would be β1+ 10*f

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How much does it cost to operate a 25-w soldering iron for 8.0 hours if energy costs 8.0¢/kwh?
melamori03 [73]
The power P is defined as the energy E per unit of time t:
P= \frac{E}{t}
In our problem, the power is P=25 W and the total time is t=8.0h, so we can calculate the total energy used during this time:
E=Pt=(25 W)(8.0 h)=200 Wh=0.2 kWh
The energy costs 8€ per each kwh, so we can write the following proportion:
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6 0
2 years ago
Which equation could be rearranged to calculate the frequency of a wave?
777dan777 [17]

Answer:

wavelength = speed/frequency

Explanation:

Required

Determine which of the options can be used to calculate frequency

The relationship between wavelength, speed and frequency is as follows;

Frequency = \frac{Wave\ Speed}{Wave\ Length} ---- Equation 1

When option (1), (2) and (4) are rearranged, they do not result in the above formula; only option (3) does

Checking option (3)

Wave\ Length = \frac{Speed}{Frequency}

Multiply both sides by Frequency

Wave\ Length * Frequency = \frac{Speed}{Frequency} * Frequency

Wave\ Length * Frequency = Speed

Divide both sides by Wave Length

\frac{Wave\ Length * Frequency}{Wave\ Length} = \frac{Speed}{Wave\ Length }

Frequency = \frac{Speed}{Wave\ Length } --- Equation 2

<em>Comparing equation 1 and 2; both equations are the same.</em>

<em>Hence, option (3) answers the question</em>

7 0
2 years ago
You go to an amusement park with your friend Betty, who wants to ride the 70-m-diameter Ferris wheel. She starts the ride at the
Ksenya-84 [330]

Answer:

Part a)

d = 23.94 m

Part b)

\theta = 110 degree

Explanation:

Part a)

As we know that initially the position vector is r

then the same magnitude position vector is rotated by 40 degree angle

so displacement magnitude is the magnitude of change in position vector

so it is given as

d = \sqrt{r_1^2 + r_2^2 + 2r_1r_2cos(180-\theta)}

r_1 = r_2 = 35 m

d = \sqrt{35^2 + 35^2 -2(35)(35)cos40}

d = 23.94 m

Part b)

now we need to find the direction of the displacement vector

so let say it makes an angle with x axis so we have

tan\theta = \frac{rsin\phi}{r - rcos\phi}

tan\theta = \frac{sin 40}{1 - cos40}

\theta = 110 degree

4 0
2 years ago
Waves inwhich the particles vibrate at right angles to direction is called
liberstina [14]
When the particles<span> of a medium are </span>vibrating at right angles<span> to the </span>direction<span> of energy transport, then the </span>wave<span> is a ____ </span>wave<span>. In transverse </span>waves<span>, </span>particles<span> of the medium </span>vibrate<span> to and from in a </span>direction<span> perpendicular to the </span>direction<span> of energy transport. </span>
5 0
2 years ago
A responder can protect himself/herself from radiation by using shielding as a response action. What materials are best for prot
Irina-Kira [14]

Answer:

Few millimeter thick aluminium, water, wood, acrylic glass or plastic.

Explanation:

The materials that are best for protection against beta particles are few millimeter thickness of aluminium, but for the high energy beta-particles radiations the low atomic mass materials such as plastic, wood, water and acrylic glass can be used.

These materials can also be used in personal protective equipment which includes all the clothing that can be worn to prevent any injury or illness due to the exposure to radiation.

3 0
2 years ago
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