The power P is defined as the energy E per unit of time t:

In our problem, the power is P=25 W and the total time is t=8.0h, so we can calculate the total energy used during this time:

The energy costs 8€ per each kwh, so we can write the following proportion:

where x is the price corresponding to 0.2 kWh. Solving the proportion we find x:

€
Answer:
wavelength = speed/frequency
Explanation:
Required
Determine which of the options can be used to calculate frequency
The relationship between wavelength, speed and frequency is as follows;
---- Equation 1
When option (1), (2) and (4) are rearranged, they do not result in the above formula; only option (3) does
Checking option (3)

Multiply both sides by Frequency


Divide both sides by Wave Length

--- Equation 2
<em>Comparing equation 1 and 2; both equations are the same.</em>
<em>Hence, option (3) answers the question</em>
Answer:
Part a)

Part b)

Explanation:
Part a)
As we know that initially the position vector is r
then the same magnitude position vector is rotated by 40 degree angle
so displacement magnitude is the magnitude of change in position vector
so it is given as




Part b)
now we need to find the direction of the displacement vector
so let say it makes an angle with x axis so we have



When the particles<span> of a medium are </span>vibrating at right angles<span> to the </span>direction<span> of energy transport, then the </span>wave<span> is a ____ </span>wave<span>. In transverse </span>waves<span>, </span>particles<span> of the medium </span>vibrate<span> to and from in a </span>direction<span> perpendicular to the </span>direction<span> of energy transport. </span>
Answer:
Few millimeter thick aluminium, water, wood, acrylic glass or plastic.
Explanation:
The materials that are best for protection against beta particles are few millimeter thickness of aluminium, but for the high energy beta-particles radiations the low atomic mass materials such as plastic, wood, water and acrylic glass can be used.
These materials can also be used in personal protective equipment which includes all the clothing that can be worn to prevent any injury or illness due to the exposure to radiation.