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kiruha [24]
2 years ago
6

You can enter units that are combinations of units with prefixes. however, you must maintain the same unit system given in the p

roblem. for example, this question uses the si unit system. therefore an answer in u.s. customary units, such as miles per hour would not be accepted as correct. a car traveling with constant speed travels 150 km in 7200 s. what is the speed of the car?

Physics
2 answers:
gtnhenbr [62]2 years ago
8 0

Speed ​​of the car: 20,833 m/s (or 21 m/s, two significant figures)

<h3>Further explanation</h3>

Regular straight motion is the motion of objects on a straight track that has a fixed speed

Formula used

\large {\boxed {\bold {S = v \times \: t}}}

S = distance = m

v = speed = m / s

t = time = seconds

Straight motion changes regularly are the straight motion of objects that have a fixed acceleration

Formula used

\large {\boxed {\bold {St = vo.t + \frac {1} {2} at ^ 2}}}

V = vo + at

Vt² = vo² + 2as

St = distance on t

vo = initial speed

vt = speed on t

a = acceleration

Each country usually has its own unit system. For example in the UK with inches and feet, Indonesia with "hasta", etc.

With the existence of these various units, we also need a variety of measuring devices in accordance with the specified units, and also conversion is needed from one unit to another. Therefore it is now agreed that there is a unit that is used as a standard that is an international system unit abbreviated as SI

There are 7 standard SI units used, namely:

  • 1.meter (m) unit length,
  • 2. kilograms (kg), units of mass
  • 3. second (s), unit of time
  • 4. ampere (A), unit of current
  • 5. kelvin (K), unit of temperature
  • 6. candela (cd), the unit of light intensity
  • 7. mole, concentration unit

The velocity itself is a quantity derived from the magnitude of length and time in SI units, m/s

A car traveling with constant speed travels 150 km in 7200 s

Here we know the distance traveled by the car = 150 km. We convert to SI units, namely m, to:

150 km = 150,000 m

while the time = 7200 s, it's already SI

Car speed is a straight-line motion because the speed is constant so the speed of the car:

V = S : t

V = 150,000 m : 7200 s

v = 20,833 m/s round up to two significant figures become 21 m/s

<h3>Learn more</h3>

The distance of the elevator

brainly.com/question/8729508

resultant velocity

brainly.com/question/4945130

the average velocity

brainly.com/question/5248528

Keywords: car, distance, speed, time

Aleks04 [339]2 years ago
7 0

Answer:

Speed of car is 20.83 m/s

Speed of car is 75 km/h

Explanation:

Distance the car travels is 150 km

SI unit of distance is meters

1000\ m=1\ km\\\Rightarrow 150\ km=150\times 1000\\\Rightarrow 150\ km=150000m

Time the car travels for is 7200 seconds which is SI units.

\text{Speed}=\frac{\text{Distance}}{\text{Time}}\\\Rightarrow \text{Speed}=\frac{150000}{7200}\\\Rightarrow \text{Speed}=20.83\ m/s

Speed of car is 20.83 m/s

Let us find the speed in km/h

1\ h=60\ s\times 60\ m\\\Rightarrow 1\ s=\frac{1}{3600}\ h\\\Rightarrow 7200\ s=\frac{7200}{3600}\\\Rightarrow 7200\ s=2\ hours

\text{Speed}=\frac{150}{2}\\\Rightarrow \text{Speed}=75\ km/h

Speed of car is 75 km/h

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balandron [24]

<em>An electron has the same amount of energy in all orbitals  is not true</em>

\boxed{\boxed{\bold{Further~explanation}}}

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Writing electron configurations starts from the lowest to the highest sub-shell energy level.

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So that the two electrons are different from just the quantum spin number, even though the other quantum numbers are the same.

So in one orbital only a maximum of 2 electrons is occupied, because if there is a third electron, this third electron will have the same quantum spin number as the previous electron

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Electron clouds show the state of electrons in their orbitals

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Statement about electrons and atomic orbitals is not true is An electron has the same amount of energy in all orbitals

the electron configuration for barium (Ba) in noble-gas notation brainly.com/question/11147367

the formation of a bond.

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8 0
2 years ago
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The Bernoulli equation is valid for steady, inviscid, incompressible flows with a constant acceleration of gravity. Consider flo
irina1246 [14]

Answer:

p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

Explanation:

first write the newtons second law:

F_{s}=δma_{s}

Applying bernoulli,s equation as follows:

∑δp+\frac{1}{2} ρδV^{2} +δγz=0\\

Where, δp is the pressure change across the streamline and V is the fluid particle velocity

substitute ρg for {tex]γ[/tex] and g_{0}-cz for g

dp+d(\frac{1}{2}V^{2}+ρ(g_{0}-cz)dz=0

integrating the above equation using limits 1 and 2.

\int\limits^2_1  \, dp +\int\limits^2_1 {(\frac{1}{2}ρV^{2} )} \, +ρ \int\limits^2_1 {(g_{0}-cz )} \,dz=0\\p_{1}^{2}+\frac{1}{2}ρ(V^{2})_{1}^{2}+ρg_{0}z_{1}^{2}-ρc(\frac{z^{2}}{2})_{1}^{2}=0\\p_{2}-p_{1}+\frac{1}{2}ρ(V^{2}_{2}-V^{2}_{1})+ρg_{0}(z_{2}-z_{1})-\frac{1}{2}ρc(z^{2}_{2}-z^{2}_{1})=0\\p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

there the bernoulli equation for this flow is p+\frac{1}{2}ρV^{2}+ρg_{0}z-\frac{1}{2}ρcz^{2}=constant

note: ρ=density(ρ) in some parts and change(δ) in other parts of this equation. it just doesn't show up as that in formular

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2 years ago
A child blows a leaf straight up in the air from rest. The leaf accelerates at 1.0\,\dfrac{\text m}{\text s^2}1.0 s 2 m1, point,
Neko [114]

Answer:

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Explanation:

As we know that initial velocity of the leaf is given as

v_i = 0

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a = 1 m/s^2

The displacement of leaf in upward direction is

d = 1 m

so now we have

d = v_i t + \frac{1}{2}at^2

1 = 0 + \frac{1}{2}(1) t^2

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2 years ago
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Answer:

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We have to find the units comprise the pound.

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Therefore,

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Therefore, we can write as 1 pound is equal to the product of slug and ft/square second.

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6 0
2 years ago
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Dmitrij [34]

Answer: B

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2 years ago
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