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Wewaii [24]
1 year ago
14

The air around a pool and the water in the pool receive equal amounts of energy from the sun. Why does the air experience a grea

ter increase in temperature than does the water?
A.
The specific heat of water is less than that of air.

B.
The specific heat of water is greater than that of air.

C.
The latent heat of water is less than that of air.

D.
The latent heat of water is greater than that of air.
Physics
1 answer:
labwork [276]1 year ago
4 0

Answer:

A

Explanation:

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Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m. At the bottom of
adoni [48]

Answer:

3311N

Explanation:

r = radius = 600m

V = speed = 150m/s

Mass = weight = 70kg

The weight of pilot when calculated due to circular motion

W = tv

Fv = mv²/r

Fv = 70x150²/600

Fv = 79x22500/600

= 15750000/600

= 2625N

Real Weight of the pilot = m x g

= 70 x 9.8

= 686N

The apparent Weight is calculated by

Mv²/r + mg

= 2625N + 686N

= 3311 N

Therefore the apparent Weight is 3311N

6 0
1 year ago
g A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0
Margarita [4]

Answer:

Explanation:

If a particle move with time and expressed according to the formula:

f(t) = 0.01t⁴ − 0.03t³

a) Velocity is the change in motion of the particle with respect to time and it is expressed as;

v(t) =\frac{d(f(t))}{dt}

v(t) = 4(0.01)t^{4-1} - 3(0.03)t^{3-1}\\v(t) = 0.04t^3 - 0.09t^2

Hence the velocity of the particle at time t is v(t) = 0.04t^3 - 0.09t^2

b) To calculate the velocity after 1 second, we will substitute t = 1 into the function v(t) in (a) as shown:

v(t) = 0.04t^3 - 0.09t^2\\v(1) = 0.04(1)^3 - 0.09(1)^2\\v(t) = 0.04 - 0.09\\v(t) = -0.05

Hence the velocity after 1second is -0.05

c) The particle is at rest when when the time is zero.

Initially, the body is not moving and the time during this time is 0. Hence the particle is at rest when t = 0second

6 0
2 years ago
A cup slides off a 1.1\,\text m1.1m1, point, 1, start text, m, end text high table with a speed of 1.3\,\dfrac{\text m}{\text s}
Tju [1.3M]

Answer:

<h3>0.145m</h3>

Explanation:

Using the equation of motion formula y = ut + 1/2gt² where;

y is the horizontal displacement

u is the initial velocity

g is the acceleration due to gravity

t is the time

To calculate the horizontal displacement, we need to first get the time t. Using the equation:

v = u+gt

1.3² = 0+(9.8)t

1.69 = 9.8t

t = 1.69/9.8

t = 0.172s

Substituting the time into the equation above to get y

y = 0+1/2(9.8)(0.172)²

y = 4.905(0.029584)

y = 0.145m

Hence the cup's horizontal displacement during the fall is 0.145m

8 0
2 years ago
Suppose the dim-looking headlight on the right is actually a small light on the front of a bicycle. What can you conclude about
aleksley [76]

Answer:

Explanation:

The dimness of two light source, which have the same intensify depends on their distance from the observer. That is why some stars appear brighter than the others, this is due to the distance of each of them from the earth.

The closer a light source, the brighter they appear

Now, if the right lamp has a dim light actually, it shows that the bicycle is closer than it appears.

4 0
2 years ago
Two teams are pulling a heavy chest, located at point X. The teams are 4.6 meters away from each other. Team A is 2.4 meters awa
Sladkaya [172]
For a better understanding of the question, please see attached picture that I've created.
We need to identify the other two angles by applying the Law of sine where we are given with the following values:
a = 3.2 unit
b = 2.4 unit
c = 4.6 unit
∠A = unknown
∠B = unknown
∠C = 110°

Solving for ∠B, we have:
sin C / c = sin B / b
sin 110 / 4.6 = sin B / 2.4
sin B = 2.4*sin 110 / 4.6
B = 29.36°

Solving for ∠A, we have:
sinC/c = sinA/ a
sin110 / 4.6 = sinA / 3.2
sinA = 3.2*sin110/ 4.6
A = 40.82°

Therefore, the missing angles are ∠A=40.82° and ∠B=29.36°.

3 0
2 years ago
Read 2 more answers
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