Answer:
3311N
Explanation:
r = radius = 600m
V = speed = 150m/s
Mass = weight = 70kg
The weight of pilot when calculated due to circular motion
W = tv
Fv = mv²/r
Fv = 70x150²/600
Fv = 79x22500/600
= 15750000/600
= 2625N
Real Weight of the pilot = m x g
= 70 x 9.8
= 686N
The apparent Weight is calculated by
Mv²/r + mg
= 2625N + 686N
= 3311 N
Therefore the apparent Weight is 3311N
Answer:
Explanation:
If a particle move with time and expressed according to the formula:
f(t) = 0.01t⁴ − 0.03t³
a) Velocity is the change in motion of the particle with respect to time and it is expressed as;


Hence the velocity of the particle at time t is 
b) To calculate the velocity after 1 second, we will substitute t = 1 into the function v(t) in (a) as shown:

Hence the velocity after 1second is -0.05
c) The particle is at rest when when the time is zero.
Initially, the body is not moving and the time during this time is 0. Hence the particle is at rest when t = 0second
Answer:
<h3>0.145m</h3>
Explanation:
Using the equation of motion formula y = ut + 1/2gt² where;
y is the horizontal displacement
u is the initial velocity
g is the acceleration due to gravity
t is the time
To calculate the horizontal displacement, we need to first get the time t. Using the equation:
v = u+gt
1.3² = 0+(9.8)t
1.69 = 9.8t
t = 1.69/9.8
t = 0.172s
Substituting the time into the equation above to get y
y = 0+1/2(9.8)(0.172)²
y = 4.905(0.029584)
y = 0.145m
Hence the cup's horizontal displacement during the fall is 0.145m
Answer:
Explanation:
The dimness of two light source, which have the same intensify depends on their distance from the observer. That is why some stars appear brighter than the others, this is due to the distance of each of them from the earth.
The closer a light source, the brighter they appear
Now, if the right lamp has a dim light actually, it shows that the bicycle is closer than it appears.
For a better understanding of the question, please see attached picture that I've created.
We need to identify the other two angles by applying the Law of sine where we are given with the following values:
a = 3.2 unit
b = 2.4 unit
c = 4.6 unit
∠A = unknown
∠B = unknown
∠C = 110°
Solving for ∠B, we have:
sin C / c = sin B / b
sin 110 / 4.6 = sin B / 2.4
sin B = 2.4*sin 110 / 4.6
B = 29.36°
Solving for ∠A, we have:
sinC/c = sinA/ a
sin110 / 4.6 = sinA / 3.2
sinA = 3.2*sin110/ 4.6
A = 40.82°
Therefore, the missing angles are ∠A=40.82° and ∠B=29.36°.