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Pepsi [2]
2 years ago
15

A fundraising company agrees to donate an extra $75 for every $100 the school raises through selling cookies. Part A: What is th

e constant of proportionality
Physics
1 answer:
Klio2033 [76]2 years ago
5 0

Answer:

3/4 0r 0.75

Explanation:

Let E represent the extra cash.

Let R represent the amount raised.

From the question given above, we can say that:

The extra cash (E) is directly proportional to the amount raised (R) i.e

Extra cash (E) ∝ Amount raised (R)

E ∝ R

E = KR

NOTE: K is the constant of proportionality.

With the above formula, we can obtain the value of K as follow:

Extra cash (E) = $ 75

Amount raised (R) = $ 100

Constant of proportionality (K) =?

E = KR

75 = K × 100

Divide both side by 100

K = 75/100

K = 3/4 0r 0.75

Thus, the constant of proportionality is 3/4 0r 0.75

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A handbag weighing 162N is carried by two students each holding the handle of the bag next to him. If each handle is inclined at
Mashcka [7]

Answer:

162N

Explanation: resolving into components and equating both vertical components equal to 162 as explained in attachment

Download pdf
3 0
2 years ago
Which of the following statements are true?A. The decrease in the amplitude of an oscillation caused by dissipative forces is ca
Umnica [9.8K]

Answer:

right A, B, C, D

Explanation:

They ask which statements are true

A) Right. The decrease in amplitude is due to the dissipation of energy by friction and is called damping

B) Right. In resonant processes the amplitude of the oscillation increases, being a forced oscillation

C) Right. In a system with energy loss, the amplitude must decrease, therefore energy must be supplied to compensate for the loss.

D) Right. It is a resonant process the driving force keeps the oscillation of the system

7 0
2 years ago
At a certain depth in the ocean. the absolute pressure is p. If you 90 to twice that depth (treating the water as incompressible
KatRina [158]

Answer:

correct option is B

the absolute pressure will be less than 2p

Explanation:

given data

absolute pressure = p

depth = twice

to find out

what is correct option

solution

we know here that p absolute pressure so we consider atmospheric pressure p1

so we can say at some depth h pressure will be

pressure p = p1 + ρ g h

so if depth is double

pressure will be

2p = 2p1 +2 (ρ g h )

so

2p - p1 = p1 + 2 (ρ g h )

so correct option is B

the absolute pressure will be less than 2p

5 0
2 years ago
A box is being pulled by two ropes. Eduardo pulls to the left with a force of 500 N, and Clara pulls to the right with a force o
sergejj [24]

Answer:

kinetic friction or something else

Explanation:

Draw a diagram to illustrate the problem, as shown below.

m = mass of the box, kg

mg =  weight of the box, N, acting downward

Because of Newton's 3rd law, a normal force of N = mg acts upward on the box.

C = 200 N, the force applied by Clara, horizontally to the right

E = 500 N, the force applied by Eduardo, horizontally to the left.

Because E is greater than C, the box will move left.

The frictional force, F, will resist the initial motion. Its magnitude is

F = μN = μmg, where μ = kinetic coefficient of friction.

F acts horizontally to the right.

From the given table, we can conclude that

Normal force acting upward is correct

Tension by Eduardoacting left is correct.

Tension by Clara acting right is correct.

Kinetic friction acting left is Incorrect.

Gravity acting downward is correct.correct

Answer:

The direction of the kinetic friction force is incorrect

8 0
2 years ago
The owner of the gas station wants to bury the gasoline so deep that no vacuum pump will be able to extract it. He has hired a g
zloy xaker [14]

Answer:

The depth of tank so that 13.49 m

Explanation:

As pressure is given as

P=\rho g h

here

  • P is the pressure which in order to avoid siphoning by any vacuum pump is atmospheric pressure. i.e. P=1.013 x10^5 Pa
  • ρ is the density of the gasoline which is calculated from the following equation of specific gravity. Assume the specific gravity of gasoline is 0.766

                                       \rho=S.G \times \rho_{w}\\\rho=0.766 \times 1000 kg/m^3\\\rho=766 kg/m^3

  • h is the depth which is to be calculated here .

                                        P=\rho g h\\h=\frac{P}{\rho g}\\h=\frac{1.013 \times 10^5}{766 \times 9.8}\\h=13.49 m

So the depth of tank so that 13.49 m

6 0
2 years ago
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