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1 year ago

2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind

Physics

1 answer:

Alex777 [14]1 year ago

5 0

The resultant speed of the plane is (3) 226 m/s

Why?

We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).

So, calculating we have:

$ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}$

$ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}$

Hence, we have that the resultant speed of the plane is (3) 226 m/s

Have a nice day!

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Answer:

No, i disagree.

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2 years ago

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(a) Greater

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$f_n = n f_1$

So we have:

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For standing waves on a string, the fundamental frequency is given by the formula:

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where

v is the speed at which the waves travel back and forth on the wire

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