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Fofino [41]
1 year ago
15

In a sample of 18-karat gold, 75 percent of the total mass is pure gold, while the rest is typically 16 percent silver and 9 per

cent copper. If the density of pure gold is rhogold=19.3g/cm3, while the densitites of silver and copper are respectively rhosilver=10.5g/cm3 and rhocopper=8.90g/cm3, what is the overall density rho18kt of this alloy of 18-karat gold?
Physics
1 answer:
ivann1987 [24]1 year ago
8 0

Answer:

15.57 g/cm³

Explanation:

\rho_g = Density of gold = 19.3 g/cm³

\rho_s = Density of silver = 10.5 g/cm³

\rho_c = Density of copper = 8.9 g/cm³

Assuming total mass as 1000 g

Volume of gold

V_g=\frac{0.75\times 1000}{19.3}\\\Rightarrow V_g=38.86\ cm^3

Volume of silver

V_g=\frac{0.16\times 1000}{10.5}\\\Rightarrow V_g=15.238\ cm^3

Volume of copper

V_c=\frac{0.09\times 1000}{8.9}\\\Rightarrow V_c=10.11\ cm^3

Density of the alloy would be

\rho=\frac{M}{V_g+V_s+V_c}\\\Rightarrow \rho=\frac{1000}{38.86+15.238+10.11}\\\Rightarrow \rho=15.57\ g/cm^3

The overall density of this alloy is 15.57 g/cm³

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arlik [135]

Answer:

The magnitude of the torque on the loop due to the magnetic field is 4.7\times10^{-4}\ N-m.

Explanation:

Given that,

Diameter = 10 cm

Current = 0.20 A

Magnetic field = 0.30 T

Unit vectorn=-0.60\hat{i}-0.080\hat{j}

We need to calculate the torque on the loop

Using formula of torque

\tau=NIAB\sin\theta

Where, N = number of turns

A = area

I = current

B = magnetic field

Put the value into the formula

\tau=1\times0.20\times\pi\times(5\times10^{-2})^2\times0.30\times\sin90^{\circ}

\tau=4.7\times10^{-4}\ N-m

Hence, The magnitude of the torque on the loop due to the magnetic field is 4.7\times10^{-4}\ N-m.

5 0
1 year ago
Which of the following is the correct definition of conduction? A. the transfer of heat by currents within a liquid or gas B. th
dolphi86 [110]
I believe it's B. the transmission of heat across matter
6 0
2 years ago
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A second baseman tosses the ball to the first baseman, who catches it at the same level from which it was thrown. The throw is m
Anit [1.1K]
 <span>(a) 

Taking the angle of the pitch, 37.5°, and the particle's initial velocity, 18.0 ms^-1, we get: 

18.0*cos37.5 = v_x = 14.28 ms^-1, the projectile's horizontal component. 

(b) 
To much the same end do we derive the vertical component: 

18.0*sin37.5 = v_y = 10.96 ms^-1 

Which we then divide by acceleration, a_y, to derive the time till maximal displacement, 

10.96/9.8 = 1.12 s 

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<span>2.24 s

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We can learn a lot about the properties of a star by studying its spectrum. All of the followingstatements are true except one.
Kisachek [45]

Answer:

B. The total amount of light in the spectrum tells us the star’s radius.

Explanation:

A.

The effective temperature of a star can be determined by means of its spectrum¹ and Wien's displacement law.                    

Since stars behave in a local way as a blackbody, it will take the wavelength at which is the peak of emission greater in the continuum (see the image below).

Then, the maximum peak of emission (\lambda_{max}) will be replaced in the next equation of the Wien's displacement law:

T = \frac{2.898x10^{-3} m. K}{\lambda max}  (1)

Where T is the effective temperature of the star.

Bodies that are hot enough emits light as consequence of its temperature. For example, a iron bar in contact with fire will start to change colors as the temperature increase, until it gets to a blue color, which its know as Wien's displacement law. Which establishes that the peak of emission for the spectrum will be displaced to shorter wavelengths as the temperature increase.

The same scenario described above can be found in the stars, a star whit higher temperature will have a blue color and one with lower temperature, a red color.

B.

Since star does not have the same size, they have different brightness, That is because the photons have a free mean path greater in a bigger radius.

So a star brightness is a consequence of its radius.

               

C.  

Spectral lines will be shifted to the blue part of the spectrum1 if the source of the observed light is moving toward the observer, or to the red part of the spectrum when it is moving away from the observer (that is known as the Doppler effect).        

By using that shift in the spectral lines, the Doppler velocity can be determined.

v = c\frac{\Delta \lambda}{\lambda_{0}}  (2)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the wavelength at rest, v is the velocity of the source and c is the speed of light.

   

D.

When a photon is absorbed by an electron in an atom of a particular element in the star photosphere, the electron will be pass to a higher state, when it comes back to the ground state, a photon will be emitted again. If the emitted photon does not go in the same direction of the incident photon an absorption line will be created in the spectrum of the star.          

This patterns of spectral lines in the spectrum of the star are compared with the patterns that are got by lamps of that element in a laboratory.

Key term:

¹Spectrum: decomposition of light in its characteristic colors (wavelengths).

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Answer: check the attached graph for the answer

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