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morpeh [17]
2 years ago
11

A golf ball is hit by a club. The graph shows the variation with time of the force exerted on the bal

Physics
2 answers:
sammy [17]2 years ago
6 0

Answer:

D the maximum acceleration of the ball

Explanation:

A the average force on the ball

Total change in momentum of the ball is area under the graph between force and time

So here average force is the ratio of area under the force time graph and total time of the graph

B the change in momentum of the ball

Total change in momentum of the ball is area under the graph between force and time

C the contact time between the ball and the club

Here total time of contact is the total time for which force is acting on the ball due to wall

D the maximum acceleration of the ball

Here since we do not know about the mass of ball we can not find the acceleration.

So here we have correct answer as

D the maximum acceleration of the ball

emmasim [6.3K]2 years ago
5 0
You can't find the acceleration of the ball. The graph tells the force, but you'd also need to know the mass of the ball.
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four children pull on the same stuffed toy at the same time , yet there is no net force on the toy.how is this possible?
Kay [80]
There was no net force on the stuffed toy, because the kids might have the same strength,  The same force is on both sides of it.  T<span>hey cancel each other out. They exert a force on the stuffed toy equal in strength but opposite in direction. The forces are balanced and the stuffed toy does not move.  </span>Its like a game of tug-o-war, but you and I have the same strength. the rope would be still and not moving. 
3 0
2 years ago
Read 2 more answers
How many turns should a 10-cm long ideal solenoid have if it is to generate a 1.5-mT magnetic field when 1.0 A of current runs t
Ira Lisetskai [31]

Answer:

N=119.34 turns

Explanation:

The magnetic field of a solenoid is calculated using the formula:

B= µo*\frac{I*N}{L} Equation 1

Where:

B: magnetic field in Teslas (T)

µo: free space permeability in T*m/A

I= Intensity of the current flowing through the conductor in ampere (A)

N= number of turns

L= solenoid length in meters (m)

Data of the problem:

L=10cm=10*10^{-2}, B= 1.5mT=1.5*10^{-3} T  ,I=1A  

µo=4\pi *10^{-7} \frac{T*m}{A}

We cleared N of the equation (1):

N=B*L/ µo*I

N= (1.5*10^{-3} *10*10^{-2} )/(4\pi *10^{-7} *1

N=0.1193*10^{3}

Answer

N=119.34 turns

3 0
2 years ago
An 1876 N crate is being pushed across a level force at a constant speed by a force of 747 N. What is the coefficient of kinetic
nekit [7.7K]

The crate only moves horizontally, so its net vertical force is 0. The only forces acting in the vertical direction are the crate's weight (pointing downward) and the normal force of the surface on the crate (pointing upward). By Newton's second law, we have

∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0   →   <em>n</em> = <em>mg</em> = 1876 N

where <em>n</em> is the magnitude of the normal force.

In the horizontal direction, the crate is moving at a constant speed and thus with no acceleration, so it's completely in equilibrium and the net horizontal force is also 0. The only forces acting on it in this direction are the 747 N push (pointing in the direction of the crate's motion) and the kinetic friction opposing it (pointing in the opposite direction). By Newton's second law,

∑ <em>F</em> (horizontal) = 747 N - <em>f</em> = 0   →   <em>f</em> = 747 N

The frictional force is proportional to the normal force by a factor of the coefficient of kinetic friction, <em>µ</em>, such that

<em>f</em> = <em>µn</em>   →   <em>µ</em> = <em>f</em> / <em>n</em> = (747 N) / (1876 N) ≈ 0.398188 ≈ 0.40

8 0
2 years ago
The mass m1 enters from the left with velocity v0 and strikes a mass m2 &gt; m1 which is initially at rest. The collision betwee
enot [183]

Answer:

1. False 2) greater than. 3) less than 4) less than

Explanation:

1)

  • As the collision is perfectly elastic, kinetic energy must be conserved.
  • The expression for the final velocity of the mass m₁, for a perfectly elastic collision, is as follows:

        v_{1f} = v_{10} *\frac{m_{1} -m_{2} }{m_{1} +m_{2}}

  • As it can be seen, as m₁ ≠ m₂, v₁f ≠ 0.

2)

  • As total momentum must be conserved, we can see that as m₂ > m₁, from the equation above the final momentum of m₁ has an opposite sign to the initial one, so the momentum of m₂ must be greater than the initial momentum of m₁, to keep both sides of the equation balanced.

3)    

  • The maximum energy stored in the in the spring is given by the following expression:

       U =\frac{1}{2} *k * A^{2}

  • where A = maximum compression of the spring.
  • This energy is always the sum of the elastic potential energy and the kinetic energy of the mass (in absence of friction).
  • When the spring is in a relaxed state, the speed of the mass is maximum, so, its kinetic energy is maximum too.
  • Just prior to compress the spring, this kinetic energy is the kinetic energy of m₂, immediately after the collision.
  • As total kinetic energy must be conserved, the following condition must be met:

       KE_{10} = KE_{1f}  + KE_{2f}

  • So, it is clear that KE₂f  < KE₁₀
  • Therefore, the maximum energy stored in the spring is less than the initial energy in m₁.

4)

  • As explained above, if total kinetic energy must be conserved:

        KE_{10} = KE_{1f}  + KE_{2f}

  • So as kinetic energy is always positive, KEf₂ < KE₁₀.
4 0
1 year ago
Calculate the density of mercury if 500 cm3
notka56 [123]

Answer:

The density of the mercury is 13.2 g/cm³

Explanation:

Density is a measurement that compares the amount of matter an object

has to its volume

Density is equal to mass divided by volume

We need to find the density of mercury if 500 cm³ has a mass of

6.60 kg in g/cm

We must to change The kilogram to grams

The mass of mercury is 6.60 kilograms

1 kilogram = 1000 grams

6.60 kilograms = 6.60 × 1000 = 6600 grams

Density = mass ÷ volume

The volume of the mercury is 500 cm³

The density = 6600 ÷ 500

The density = 13.2 g/cm³

<em>The density of the mercury is 13.2 g/cm³ </em>

5 0
2 years ago
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