Answer:
C) 160 N
Explanation:
= mass of the car = 2000 kg
Weight of the car is given as
= Force exerted on the input piston
= Area of input piston = 10 cm x 10 cm = 0.1 m x 0.1 m = 0.01 m²
= Area of lift = 1 m x 1.2 m = 1.2 m²
Using Pascal's law
1) They are able to balance the torques due to gravity.
The torque is equal fo Force * lever arm.
The force downward is due to gravity, Force = mass*gravity.
Then the heavier student will produce a bigger force downgar and he/she shall shorten the lever arm of his/her side, by placing himself closer to the rotation axis, than the lighter student.
I'm thinking that you're supposed to divide. So you would divide 5 into 60 and get 12
<u>Answer:</u>
<em>Newtons II law: </em>
<em> </em>It is defined as<em> "the net force acting on the object is a product of mass and acceleration of the body"</em> . Also it defines that the <em>"acceleration of an object is dependent on net force and mass of the body".</em>
Let us assume that,a string is attached to the cart, which passes over a pulley along the track. At another end of the string a weight is attached which hangs over the pulley. The hanging weight provides tension in the spring, and it helps in accelerating the cart. We assume that the string is massless and no friction between pulley and the string.
Whenever the hanging weight moves downwards, the cart will accelerate to right side.
<em>For the hanging weight/mass</em>
When hanging weight of mass is m₁ and accelerate due to gravitational force g.
Therefore we can write F = m₁ .g
and the tension acts in upward direction T (negetive)
Now, Fnet = m₁ .g - T
= m₁.a
So From Newtons II law<em> F = m.a</em>
We are given the following values:
weight w = 240 lb = 1,067.52 N
energy E = 3,000 J
The formula for potential energy is:
E = w h
where h is the height the person has to climb, therefore:
h = 3000 / 1067.52
<span>h = 2.81 m</span>
<span>
</span>
<span>Therefore he has to climb 2.81 meters</span>
