...the potential energy that you build while going up the hill on the roller coaster could be let go as kinetic energy -- the energy of motion that takes you down the hill of the roller coaster.
Answer:
V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)
Explanation:
Attached is the full solution
Summary:
a= 12.0 m/(s^2)
v= 100m/s
t1= 2.0s => s1=?
t2=5.0s => s2=?
t3=10.0s => s3=?
——————
Solution:
• when t1=2.0 s, I have gone:
S1= v*t1 + 1/2*a*(t1^2)
=100.0 *2 + 1/2*12.0*(2.0^2)
=224 (m)
• when t2=5.0s, I have gone
S2=v*t2+ 1/2*a*(t2^2)
= 100*5.0+ 1/2*12.0*(5.0^2)
=650 (m)
•when t3= 10.0s, I have gone:
S3=v*t3+ 1/2*a*(t3^2)
=100*10.0+ 1/2*12*(10.0^2)
=1600 (m)
Answer:
I1 = 0.772 A
Explanation:
<u>Given</u>: R1 = 5.0 ohm, R2 = 9.0 ohm, R3 = 4.0 ohm, V = 6.0 Volts
<u>To find</u>: current I = ? A
<u>Solution: </u>
Ohm's law V= I R
⇒ I = V / R
In order to find R (total) we first find R (p) fro parallel combination. so
1 / R (p) = 1 / R1 + 1/ R2 ∴(P) stand for parallel
R (p) = R1R2 / ( R1 + R2)
R (p) = (5.0 × 9.0) / (5.0 + 9.0)
R (p) = 3.214 ohm
Now R (total) = R (p) + R3 (as R3 is connected in series)
R (total) = 3.214 ohm + 4.0 Ohm
R (total) = 7.214 ohm
now I (total) = 7.214 ohm / 6.0 Volts
I (total) = 1.202 A
This the total current supplied by 6 volts battery.
as voltage drop across R (p) = V = R (p) × I (total)
V (p) = 3.214 ohm × 1.202 A = 3.864 volts
Now current through 5 ohms resister is I1 = V (P) / R1
I1 = 3.864 volts / 5 ohm
I1 = 0.772 A
Answer:
F. jumping
Explanation:
you can't throw/toss yourself, you cant roll over water, catching?, you cant run over water, jumps are bigger than hops
