Answer:
F = 1500 N
F/W = 500:147
Explanation:
Using the equation of motion, to get the initial velocity
v² = u²+2gs ............. Equation 1
Where v =final velocity, u = initial velocity, a = acceleration, s = distance.
make a the subject of the equation
Given: v = 0 m/s ( at the maximum height), s = 2.5 m, g = -9.8 m/s²(against gravity)
substitute into equation 1
0² = u² +2×2.5×(-9.8)
u² = 49
u = 7 m/s.
a = u/t
Where t = time = 0.21 s
a = 7/0.21
a = 33.33 m/s²
Recall that,
F = ma ........... Equation 2
Where F = force, m = mass of the impala.
Given: m = 45 kg and a =33.33 m/s²
Substitute into equation 2
F = 45(33.33)
F =1500 N.
Hence the force =1500 N.
Weight of the antelope = mg
W = mg
Where m = 45 kg, g = 9.8
W = 441 N.
F/W =1500/441
F/W = 500:147
Hence the ratio of force to antelope weight = 500:147
