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2 years ago

13

A pronghorn antelope has been observed to run with a top speed of 97 km/h. Suppose an antelope runs 1.5 km with an average speed

of 85 km/h, then runs 0.80 km with an average speed of 67 km/h

1 answer:

Angelina_Jolie [31]2 years ago

4 0

Answer:

10

Explanation:

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A charge of 87.6 pC is uniformly distributed on the surface of a thin sheet of insulating material that has a total area of 65.2

LiRa [457]

Answer:

60.8 cm²

Explanation:

The charge density, σ on the surface is σ = Q/A where q = charge = 87.6 pC = 87.6 × 10⁻¹² C and A = area = 65.2 cm² = 65.2 × 10⁻⁴ m².

σ = Q/A = 87.6 × 10⁻¹² C/65.2 × 10⁻⁴ m² = 1.34 × 10⁻⁸ C/m²

Now, the charge through the Gaussian surface is q = σA' where A' is the charge in the Gaussian surface.

Since the flux, Ф = 9.20 Nm²/C and Ф = q/ε₀ for a closed Gaussian surface

So, q = ε₀Ф = σA'

ε₀Ф = σA'

making A' the area of the Gaussian surface the subject of the formula, we have

A' = ε₀Ф/σ

A' = 8.854 × 10⁻¹² F/m × 9.20 Nm²/C ÷ 1.34 × 10⁻⁸ C/m²

A' = 81.4568/1.34 × 10⁻⁴ m²

A' = 60.79 × 10⁻⁴ m²

A' ≅ 60.8 cm²

6 0

2 years ago

true or false:acceleration toward the center of a curved or circular path is called gravitational acceleration.

nalin [4]

Nope. It's called 'centripetal' acceleration. The force that created it MAY be gravitational, but it doesn't have to be. For things on the surface of the Earth moving in circles, it's never gravity.

5 0

2 years ago

A 120-kg refrigerator that is 2.0 m tall and 85 cm wide has its center of mass at its geometrical center. You are attempting to

Mademuasel [1]

To solve this problem it is necessary to apply the concepts related to Force of Friction and Torque given by the kinematic equations of motion.

The frictional force by definition is given by

$F= \mu mg$

Our values are here,

$\mu=0.3$

$m=120kg$

$g=9.8m/s^2$

Replacing,

$F=0.30*120*9.8 = 352.8N$

Consider the center of mass of the body half its distance from the floor, that is d = 0.85 / 2 = 0.425m. The torque about the lower farther corner of the refrigerator should be zero to get the maximum distance, then

$F*x = mg*d$

Re-arrange for x,

$x= \frac{mg*d}{F}$

$x= \frac{mg*d}{\mu mg}$

$x= \frac{d}{\mu}$

$x= \frac{0.425}{0.3}$

$x = 1.42m$

Then we can conclude that 1.42m is the distance traveled before turning.

6 0

2 years ago

Which statement describes one way in which global winds affect weather and climate? A. Polar easterlies move warm air to the mid

Genrish500 [490]

The answer your looking for is "D".

4 0

2 years ago

Read 2 more answers

A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equa

kozerog [31]

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

given,

weight of the person = 625 N

weight of the bike = 98 N

Pressure on each Tyre = 7.60 x 10⁵ Pa

Area of contact on each Tyre = ?

total weight of the system = 625 + 98

= 723 N

Let F be the force on both the Tyre

F + F = W

2 F = 723

F = 361.5 N

F = P A

$A = \dfrac{F}{P}$

$A = \dfrac{361.5}{7.60 \times 10^5}$

A = 4.76 x 10⁻⁴ m²

7 0

2 years ago